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    select s.hacker_id , h.name from submissions s join challenges c on s.challenge_id = c.challenge_id join difficulty d on c.difficulty_level = d.difficulty_level join hackers h on s.hacker_id = h.hacker_id where s.score = d.score group by s.hacker_id, h.name having count() > 1 order by count() desc, s.hacker_id;