Top Competitors

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    select h.name,s.hacker_id,s.score from Submissions s join Challenges c on s.challenge_id = c.challenge_id join Difficulty d on d.difficulty_level = c.difficulty_level join Hackers h on h.hacker_id = s.hacker_id where d.score = s.score group by s.hacker_id,s.score,h.name having count(s.hacker_id) > 1 order by s.score desc,s.hacker_id asc;