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SELECT h.hacker_id, h.name
FROM submissions s
JOIN challenges c
ON s.challenge_id = c.challenge_id
JOIN difficulty d
ON c.difficulty_level = d.difficulty_level
JOIN hackers h
ON s.hacker_id = h.hacker_id
WHERE s.score = d.score
AND c.difficulty_level = d.difficulty_level
GROUP BY h.hacker_id
HAVING COUNT(s.hacker_id) > 1
ORDER BY COUNT(s.hacker_id) DESC, h.hacker_id ASC;
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SELECT h.hacker_id, h.name FROM submissions s JOIN challenges c ON s.challenge_id = c.challenge_id JOIN difficulty d ON c.difficulty_level = d.difficulty_level JOIN hackers h ON s.hacker_id = h.hacker_id WHERE s.score = d.score AND c.difficulty_level = d.difficulty_level GROUP BY h.hacker_id HAVING COUNT(s.hacker_id) > 1 ORDER BY COUNT(s.hacker_id) DESC, h.hacker_id ASC;