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  1. Prepare
  2. Algorithms
  3. Strings
  4. Funny String
  5. Discussions

Funny String

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1351 Discussions

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  • geovanni_luna
     + 0 comments

    TypeScript O(n) time and O(1) space solution:

    function funnyString(s: string): string {
    let i = 1
    let j = s.length - 2
    
    while (i < s.length && j > -1) {
        let leftVal = Math.abs(s[i -1].charCodeAt(0) - s[i].charCodeAt(0))
        let rightVal = Math.abs(s[j].charCodeAt(0) - s[j + 1].charCodeAt(0))
        
        if (leftVal !== rightVal) {
            return "Not Funny"
        } 
         
        i++
        j--
    }
    
    return "Funny"
}

  • afzal_saiyed931
     + 0 comments
    def funnyString(s):
    # Write your code here
    
    start = 0
    end = len(s) - 1
    
    while start < (len(s) - 1) and end > 0:
        first = abs(ord(s[start]) - ord(s[start + 1]))    
        second = abs(ord(s[end]) - ord(s[end - 1]))
        if first != second:
            return "Not Funny"
            
        start += 1
        end -= 1
        
    return "Funny"

  • yashdeora98294
     + 0 comments

    Here is problem solution in python java c++ c and javascript - https://programmingoneonone.com/hackerrank-funny-string-problem-solution.html

  • alban_tyrex
     + 0 comments

    Here is my simple c++ solution, video explanation here : https://youtu.be/gcNAo9voHvk.

    string funnyString(string s) {
    string r = s;
    reverse(r.begin(), r.end());
    for(int i = 1; i < s.size(); i++){
        if(abs(s[i]-s[i-1]) != abs(r[i]- r[i-1])) return "Not Funny";
    }
    return "Funny";
}

  • herlianaNoviar
     + 0 comments

    Here is my PHP solution:

    function funnyString($s) {
    // Write your code here
    $s_new = str_split($s);
    $s_new_reverse = array_reverse($s_new);
    $hasil = "Funny";
    
    for ($i=0; $i < count($s_new)-1; $i++) {
        if (abs(ord($s_new[$i]) - ord($s_new[$i+1])) !== abs(ord($s_new_reverse[$i]) - ord($s_new_reverse[$i+1]))) {
            $hasil = "Not Funny";
            break;
        }
    }
    return $hasil;
}