We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Algorithms
  3. Strings
  4. Gemstones
  5. Discussions

Gemstones

  • sawpyaeyadanar1
     + 0 comments

    Swift, Here is my idea. It is easy to understand, however it is too long

    func gemstones(arr: [String]) -> Int {
    
    var uniqueData = Set<String>()
    var result = 0
    guard let firstIndex = arr.first else { return result }
    firstIndex.map { uniqueData.insert(String($0))}
    for i in 1..<arr.count {
        var temp = Set<String>()
        arr[i].map {
            temp.insert(String($0))
        }
        
        print("uniqueData \(uniqueData) and temp is \(temp)")
        print("intersection \( uniqueData.intersection(temp))")
        var intersection =  uniqueData.intersection(temp)
        result = intersection.count
        print("result ", result)
        uniqueData = []
        uniqueData = intersection
    }
    return result
}

    Then, I refactor the code using formIntersection. we don't need the unnecessary variables

    func gemstones(arr: [String]) -> Int {
    guard let first = arr.first else { return 0 }
    var commonCharacters = Set(first.map { String($0) })
    
    for string in arr.dropFirst() {
        commonCharacters.formIntersection(string.map { String($0) })
    }
    
    return commonCharacters.count
}