We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Data Structures
  3. Linked Lists
  4. Get Node Value
  5. Discussions

Get Node Value

  • MoHazem02
     + 0 comments

    here's my C++ solution. If we can get the length of the linked list, we can get that position form the head. Why? Because I'm initially given the head pointer so I just have to count certain number from that head.

    int getNode(SinglyLinkedListNode* llist, int positionFromTail)
{
    int LSize = 0;
    SinglyLinkedListNode* counter = llist;
    while(counter)
    {
        ++LSize;
        counter = counter->next;
    }
    int positionFromHead = LSize - positionFromTail;
    while (positionFromHead-- > 1)
    {
        llist = llist->next;
    }
    return llist->data;
}