Here's a solution in C#

static SinglyLinkedListNode insertNodeAtPosition(SinglyLinkedListNode llist, int data, int position)
    {
		SinglyLinkedListNode node = new SinglyLinkedListNode(data);
        
        if(position == 0){
            node.next = llist;
            return node;
        }
        
        SinglyLinkedListNode cur = llist;
        
        for(int i = 0; i < position -  1; i++){
            if(cur != null){
                cur = cur.next;    
            }
        }
        
        node.next = cur.next;
        cur.next = node;
        
		return llist;
    }

The following code attempts to insert a node into a singly linked list at a specific position. Comment on the correctness of the logic. Identify any edge cases that may not be handled and suggest improvements if necessary. Bet Guru

def insertNodeAtPosition(llist, data, position): # Write your code here if llist is None: llist = SinglyLinkedList() llist.data = data else: current = llist for i in range(1, position): current = current.next

    new_next = SinglyLinkedList()
    new_next.data = data
    new_next.next = current.next
    current.next = new_next
return llist

Haskell boilerplate contains a mistake which makes this problem unsolvable in Haskell

"This operation requires traversing the linked list up to the node just before the desired position. It’s important to handle edge cases, such as inserting at the head (position 0) or beyond the current length of the list. Proper pointer management is critical to ensure no nodes are lost and the list remains intact." Gold365.site