giulianopietoso Yep, the "IDE" is bugged. All codes are correct but it keeps saying:
Your Output (stdout) Right Answer!
And doesn't pass.
manmohankhandel1 I am also facing the same issue
Saurabh_rajvaid1 Same here
rashmishukla1893 Yes! I am also acing the same issue.
zakarh I submitted a report on this issue. The IDE is now fixed.
abhiram_nataraj1 Still has indentation issue
O________o Still has an indentation issue http://https://imgur.com/GSKppsx
alexjvalentino 2 weeks later and it still isn't fixed.
saralbhagat0 still not fixed
shivaaprs still the same issue.
Suhasmv98 try this out:- SinglyLinkedListNode* insertNodeAtHead(SinglyLinkedListNode* llist, int data) { SinglyLinkedListNode* newnode = new SinglyLinkedListNode(data); if(llist==NULL){ llist= newnode; }else{ newnode->next = llist; llist = newnode; } return llist; }
edrouwendaal In C# the same for not unsafe PrintSinglyLinkedList(llist->head, "\n", textWriter);
alex_ge999 Still not fixed yey
gmlike4 I am also facing the same issue.
SHWAUBH Your code did not pass this test case.
Input (stdin)
3 75 226 329 722 Your Output (stdout)
Right Answer! Expected Output
722 75 226 329 Compiler Message
Wrong Answer
Please assist me on this Weird error....
Node n = new Node(); n.data=x; n.next = head; return n;
This is my Code.......yashasvishukla11 We have to print the list in reverse order
GustavK Uneditable code in C# doesn't compile as it is.
solution.cs(78,36): error CS0214: Pointers and fixed size buffers may only be used in an unsafe context solution.cs(78,36): error CS0193: The * or -> operator must be applied to a pointer Compilation failed: 2 error(s), 0 warnings
gags13_13 same issue
edordo This line in the uneditable code: PrintSinglyLinkedList(llist->head, "\n", textWriter);
Should be PrintSinglyLinkedList(llist.head, "\n", textWriter);
cristi92 how are we supposed to fix this? Are there any admins around here?
shivaaprs I am also facing the same issue. seems admnis are not looking into this.
inatan_hertzog I've the same issue too.
RupaMistry This issue is still not fixed. Not able to compile the code.
xxDOOMbox same issue, i just had to write this one in c++ ...
anilkumarsindhe Same problem.! Getting Compilation Error :( "Check the compiler output. fix the eror and try again". Compile Message says solution.cs(88,36): error CS0214:Pointers and fixed size buffers may only be used in any unsafe c ontext solution.cs(88,36): error CS0193: The * or -> operator must be applied to a pointer Compilation failed: 2 error(s), 0 warnings.
Coading language is : C#
bs436 solution.c: In function ‘main’: solution.c:111:36: error: ‘SinglyLinkedList {aka struct SinglyLinkedList}’ has no member named ‘headhead’; did you mean ‘head’? free_singly_linked_list(llist->headhead);
There is a typo in the default code and I cant edit it
PeaceMac Same thing is happening with me.
I think this bug is very recent and nobody else faced it before us!!
nicknickolaev Same here, it's obviously a typo. Nikolay
iammanoj0513 same error ...........for me also
thegirlnotknown same error!
16tucs228 sameeeee
srikarsunny444 Same here!
shubhamjain2810 it seems that this error is only in the code template for C language. This is why codes in other languages are running.
bejugamrevathi did anyone get the solution for this error
abdulrahimanbas1 same issue
vaibhav_verma261 issue isn't fixed yet...!!!
shrti_2018202010 yes same here
harika22k yes same here!!!!
manikgoel_59 sme here
king4sam990816 bug is still there...
chandan98 WRITE #define headhead head, It will work
krishnasandeep01 thank u bro
krishnasandeep01 same error is showing to me also.
chandan98 [deleted]
chandan98 WRITE #define headhead head, It will work
maa_21shubham but we can't edit the code.So how to write #define headhead head????
chandan98 yes, we can't edit the main function but do write what I have said earlier inside the insertNodeAtHead function.
ev0rtex I had the same issue with the 'C' language version. I did what others suggested and added '#define headhead head' and that got it to pass fine but there is obviously an issue in need of correcting here.
esHack Node Insert(Node head,int x) {
Node node1 =new Node(); node1.data = x; node1.next= head; return node1;}
nish456 What is the Big O notation for this code? Does creating a pointer to the head of the list actually copy it all over again one by one? if not, is it constant time?
helluvamatt O(1) aka Constant time
You are not copying anything other than the pointer to the head node into the newly created node. Linked lists are not like arrays in that you don't have to copy elements to insert/delete elements.
VirajSingh19 We should also check if head == null then there we could write a different code like head= new Node();, head.data = data and finally return head and in the else part your code should be written?
go_st_go There is no need to. If head is null then the new head of the list will point to null (that means that it is the only node in the list).
ormsson This one-liner C++14 code passed all the tests but it seems rather simple. Is it correct in general? (Sorry for noob question...)
Node* Insert(Node *head,int data) { return new Node{data, head}; }
ghanta_mounika71 ya its actual working!! but did get it
ghanta_mounika71 could u tell me....
170040676_s40 code calling recursive called function
deepakgeorge010 We are given the pointer to the head of the linked list. There are two scenarios here that we have to deal with 1. When the head node is already present 2. When the linked list is empty i.e. where there is no head node. Scenario 1: Create a node and assign data as the data of the node and pass head (the pointer to the current head of the list) to the 'next_node' parameter of the Node constructor. Scenario 2: Surprisingly the solution to the second situation is the same as well. Here, when we pass head (which in this case is NULL cos the list is empty to begin with), the new node is created with its 'next' attribute set to Null, meaning there is no second node in the list yet and the list contains only one element so far, which is the head node we just created.
Hence the two scenarios can be condensed down into one single line which is what you have done here. Hope it helped!!
alj968 I don't understand how this is not passing the test. I'm confident it's correct, so much so that I submitted it just to compare it to the solutions on the leaderboard, and even though it failed when I submitted it, it's functionally the same as correct java solutions that were submitted. There's a solution that's exactly like mine except the return is in each conditional. Is this possibly a bug with the system? Help please!
With this code:
Node Insert(Node head,int x) { Node n = new Node(); n.data = x; n.next = null; if(head == null) { head = n; } else { n.next = head; head = n; }
return head; }I get this: Your code did not pass this test case.
Your output: Right Answer!
Compiler Message: Wrong Answer
deepak111224 why it is giving indentation error in python
sampathanurag3 Even I'm facing the same error!
alexjvalentino Still hasn't been fixed. Can't complete this problem in Python yet.
atii777 It seems unfortunately the compiler is still bugged. (Right Answer!/Wrong Answer)
huangweijing We need an admin to solve this. It seems that the IDE worked well just months ago, but has broken recently. I couldn't pass through the testcase, though it outputs:
Your Output (stdout)
Right Answer!
huangweijing the problem has been fixed! Thanks.
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