Easy Python3 solution:

# Enter your code here. Read input from STDIN. Print output to STDOUT

import re

ipv4 = r'^(([01]?[0-9]?[0-9]|2[0-4][0-9]|25[0-5])\.){3}([01]?[0-9]?[0-9]|2[0-4][0-9]|25[0-5])$'
ipv6 = r'^([0-9a-fA-F]{1,4}:){7}[0-9a-fA-F]{1,4}$'

for _ in range(int(input())):
    string = input()
    if re.findall(ipv4, string):
        print('IPv4')
    elif re.findall(ipv6, string):
        print('IPv6')
    else:
        print('Neither')

for Python 3:

import re
N= int(input())

for i in range(N):
    s = input()
    try:
        regex = re.findall(r"^([\da-f]{,4}\:){7}[\da-f]{,4}$", s)
        if regex:
            print("IPv6")
        else:
            regex = re.findall(r"^((25[0-5]|2[0-4][0-9]|1[0-9][0-9]|[1-9]?[0-9])\.){3}(25[0-5]|2[0-4][0-9]|1[0-9][0-9]|[1-9]?[0-9])$", s)
            if regex:
                print("IPv4")
            else:
                print("Neither")
    except Exception as e:
        pass

Solution for JAVA with explanation:

Scanner scan = new Scanner(System.in); int n =scan.nextInt(); scan.nextLine();

String input = "";

    Pattern ipv4 = Pattern.compile("(([0]?[0-9]?[0-9]|[1][0-9][0-9]|[2][0-5][0-5])(\\.)){3}([0]?[0-9]?[0-9]|[1][0-9][0-9]|[2][0-5][0-5])");

    Pattern ipv6 = Pattern.compile("([a-f\\d]{1,4}(:){1}){7}[a-f\\d]{1,4}");
Matcher m;

for(int i=0;i<n;i++){
    input = scan.nextLine();
    m = ipv4.matcher(input);
    if(m.matches()){
        System.out.println("IPv4");
    }
    else {
        m = ipv6.matcher(input);
        if(m.matches()){
            System.out.println("IPv6");
        }
        else {
            System.out.println("Neither");
        }
    }
    input = "";
}

scan.close();

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