def isFibo(n):

a=-1
b=1
c=0
temp=False
for i in range(1,10000000):

    c=a+b

    if(c>n):
        break
    if(c==n):
        temp=True
        break

    a=b
    b=c

if(temp==True):

    return "IsFibo"
else:
    return "IsNotFibo"