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  4. Is Fibo
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Is Fibo

  • muhsen_kaamil
     + 0 comments

    Python 3 Binet's formula

    def IsFibo(n):
    return ('IsNotFibo', 'IsFibo')[any(filter(lambda x: x%1==0, (sqrt(5*n**2+4), sqrt(5*n**2-4))))]