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  1. Practice
  2. Python
  3. Itertools
  4. itertools.combinations_with_replacement()
  5. Discussions

itertools.combinations_with_replacement()

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  • mwtillotson
     + 13 comments

    Am I the only one who finds prints in list comprehensions really ugly?

    from itertools import combinations_with_replacement

s, k = input().split()

for c in combinations_with_replacement(sorted(s), int(k)):
    print("".join(c))

  • marinskiy
     + 2 comments

    Here is Python 3 solution from my HackerrankPractice repository:

    import itertools
s = input().split()
string, number = sorted(s[0]), int(s[1])
print(*list(map(''.join, itertools.combinations_with_replacement(string, number))), sep='\n')

    Feel free to ask if you have any questions :)

  • FJSevilla
     + 3 comments

    Python 3.x:

    from itertools import combinations_with_replacement as combs

s, k = input().split()
print(*[''.join(p) for p in combs(sorted(s), int(k))], sep='\n')

  • Prateek_singh73
     + 0 comments

    python 3

    from itertools import combinations_with_replacement
n,m=list(input().split())
c=list(combinations_with_replacement(sorted(n),int(m)))
for i in c:
    print("".join(i))

  • saurabh_tambolk1
     + 1 comment

    Simple Solution

    from itertools import combinations_with_replacement
s=input().split()
s[0]=sorted(s[0])
k=list(combinations_with_replacement(s[0],int(s[1])))
for i in range(len(k)):
    print(''.join(k[i]))
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