Discussion on Java 1D Array Challenge

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2 weeks ago+ 0 comments

import java.util.*;

public class Solution {

public static void main(String[] args) {

    Scanner scan = new Scanner(System.in);
    int n = scan.nextInt();

    int[] a = new int[n];

    for (int j = 0; j < n; j++) {
        a[j] = scan.nextInt();

    }

    scan.close();

    // Prints each sequential element in array a
    for (int i = 0; i < a.length; i++) {
        System.out.println(a[i]);
    }
}

}

4 weeks ago+ 0 comments

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;



public class Solution {
    public static void main(String[] args) throws IOException {
    
        Scanner sc = new Scanner(System.in);

        int integers = sc.nextInt();

        int[] myArray = new int[integers];

        for (int i = 0; i < myArray.length; i++) {
            myArray[i] = sc.nextInt();
            System.out.println(myArray[i]);
        }

    }
}

4 weeks ago+ 0 comments

import java.util.*;

public class Solution {

public static void main(String[] args) {
    int a[] = new int[5];
    Scanner scan = new Scanner(System.in);

    for (int j = 0; j < 5; j++) {
        a[j] = scan.nextInt();
    }

    scan.close();
    System.out.println("Output now");

    for (int i = 0; i < a.length - 1; i++) {
        for (int j = 0; j < a.length - i - 1; j++) {
            if (a[j] > a[j + 1]) {
                int temp = a[j];
                a[j] = a[j + 1];
                a[j + 1] = temp;
            }
        }
    }

    // Prints the sorted elements in array a
    for (int k = 0; k < a.length; k++) {
        System.out.println(a[k]);
    }
}

}

1 month ago+ 0 comments

The instructions mentions a loop, but there is no loop available for modification: "Modify the code in the loop so that it saves each sequential value to its corresponding location in the array. For example, the first value must be stored in , the second value must be stored in , and so on."

2 months ago+ 0 comments

public class Solution {
    public static void main(String[] args) throws IOException {
        Scanner scan = new Scanner(System.in);

        int n = scan.nextInt();
        
        List<Integer> arrList = new ArrayList<Integer>();
        while (scan.hasNextInt()) {
            arrList.add(scan.nextInt());
        }
        
        for(Integer i: arrList) System.out.println(i);
        
    }
}

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