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  1. Prepare
  2. Java
  3. Data Structures
  4. Java 1D Array
  5. Discussions

Java 1D Array

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280 Discussions

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  • vanshrathi361
     + 0 comments

    solution in java

            int[] a = new int[n];
        for (int i = 0; i < n; i++){
            a[i]= scan.nextInt();
        }

  • joshvajames163
     + 0 comments

    int a[]=new int[n]; for(int i=0;i<=n-1;i++) { a[i]=scan.nextInt(); }

  • yashdeora98294
     + 0 comments

    Here is Java 1D Array solution - https://programmingoneonone.com/hackerrank-java-1d-array-problem-solution.html

  • kunal_brahmank11
     + 0 comments

    Solution in java

    import java.util.*;

public class Solution {

    public static void main(String[] args) {
	   
        Scanner scan = new Scanner(System.in);
        int n = scan.nextInt();
        int a[] = new int[n];
        for(int i=0;i<a.length;i++){
            a[i]=scan.nextInt();
        }
        scan.close();

        // Prints each sequential element in array a
        for (int i = 0; i < a.length; i++) {
            System.out.println(a[i]);
        }
    }
}

  • sujaldaware7721
     + 0 comments

    public class Solution {

    public static void main(String[] args) {

    Scanner scan = new Scanner(System.in);
    int n = scan.nextInt();
    int [] a = new int[n];
    for(int i = 0;i < n; i++){
        int v = scan.nextInt();
        a[i] = v;
    }
    scan.close();

    // Prints each sequential element in array a
    for (int i = 0; i < a.length; i++) {
        System.out.println(a[i]);
    }
}

    }