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Java 1D Array

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  • rajnish_sharma_1
    3 years ago+ 5 comments

    here is the code which worked for me. Hope it works for you as well...

    import java.util.*;

    public class Solution {

    public static void main(String[] args) {
    
        Scanner scan = new Scanner(System.in);
        int n = scan.nextInt();
        int[] a = new int[n];
        for(int i = 0; i < n; i++){
            a[i]=scan.nextInt();
        }
    
        scan.close();
    
        // Prints each sequential element in array a
        for (int i = 0; i < a.length; i++) {
            System.out.println(a[i]);
        }
    }
    

    }

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  • andrE3a
    6 years ago+ 6 comments

    The Sample Output is wrong: it shows that you should also print n, but you mustn't do it because you'll not pass the tests. Please edit it.

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  • romrom_coder
    12 months ago+ 0 comments
    int[] a = new int[n];
            int index = 0;
            while(n > 0){
                a[index++] = scan.nextInt();
                n--;
            }
    
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  • anand_kanekal
    3 days ago+ 0 comments

    Solution:

    int[] a = new int[n];
            
    for(int i = 0; i < a.length; i++) {
    			a[i] = scan.nextInt();
    }
    
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  • jayswalhari
    2 weeks ago+ 0 comments

    Simple one

    int a[]=new int[n]; for(int x=0;x<n;x++){ a[x]=scan.nextInt(); }

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