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Java 1D Array
Java 1D Array
+ 5 comments here is the code which worked for me. Hope it works for you as well...
import java.util.*;
public class Solution {
public static void main(String[] args) { Scanner scan = new Scanner(System.in); int n = scan.nextInt(); int[] a = new int[n]; for(int i = 0; i < n; i++){ a[i]=scan.nextInt(); } scan.close(); // Prints each sequential element in array a for (int i = 0; i < a.length; i++) { System.out.println(a[i]); } }
}
+ 6 comments The Sample Output is wrong: it shows that you should also print n, but you mustn't do it because you'll not pass the tests. Please edit it.
+ 0 comments int[] a = new int[n]; int index = 0; while(n > 0){ a[index++] = scan.nextInt(); n--; }
+ 0 comments Solution:
int[] a = new int[n]; for(int i = 0; i < a.length; i++) { a[i] = scan.nextInt(); }
+ 0 comments Simple one
int a[]=new int[n]; for(int x=0;x<n;x++){ a[x]=scan.nextInt(); }
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