Java Anagrams

  • + 1 comment

    yes for example this is way easier to understand for some reason this did not pop to mind

    I wonder this is still faster for larger data sets

    (sayanarijit)

    static boolean isAnagram(String a, String b) {
    	char[] ca = a.toLowerCase().toCharArray();
    	char[] cb = b.toLowerCase().toCharArray();
    	Arrays.sort(ca);
    	Arrays.sort(cb);
    	return (new String(ca)).equals(new String(cb));
    }