Does anyone feel like the instructions to this challenege is kind of vague?

A simple solution that doesn't involve the Java Math Class is to use the MIN and MAX fields on the Byte, Short, Integer, and Long wrapper classes.

 try
        {
            long x=sc.nextLong();
            System.out.println(x+" can be fitted in:");
            if(x>=Byte.MIN_VALUE && x<=Byte.MAX_VALUE){
                System.out.println("* byte");
            }
            if (x>=Short.MIN_VALUE && x<=Short.MAX_VALUE){
                System.out.println("* short");
            }
            if (x>=Integer.MIN_VALUE && x<=Integer.MAX_VALUE){
                System.out.println("* int");
            }
            if (x>=Long.MIN_VALUE && x<=Long.MAX_VALUE){
                System.out.println("* long");
            }
        }

My Solution:

public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    int t=sc.nextInt();
    for(int i=0;i<t;i++)
    {
        try
        {
            long x=sc.nextLong();
            System.out.println(x+" can be fitted in:");
            if(x == (byte)x)System.out.println("* byte");
            if(x == (short)x)System.out.println("* short");
            if(x == (int)x)System.out.println("* int");
            if(x == (long)x)System.out.println("* long");
        }
        catch(Exception e)
        {
            System.out.println(sc.next()+" can't be fitted                  anywhere.");
        }

    }
}

This should work without any problem and you don't have to remember range of any Datatypes. Happy Coding!

import java.util.*;
import java.io.*;

class Solution{
    public static void main(String []argh){
        Scanner sc = new Scanner(System.in);
        int t=sc.nextInt();

        for(int i=0;i<t;i++){
            try{
                long x=sc.nextLong();
                System.out.println(x+" can be fitted in:");
                if(x>=Byte.MIN_VALUE && x<=Byte.MAX_VALUE)
                    System.out.println("* byte");
                if(x>=Short.MIN_VALUE && x<=Short.MAX_VALUE)
                    System.out.println("* short");
                if(x>=Integer.MIN_VALUE && x<=Integer.MAX_VALUE)
                    System.out.println("* int");
                if(x>=Long.MIN_VALUE && x<=Long.MAX_VALUE)
                    System.out.println("* long");
            }
            catch(Exception e){
                System.out.println(sc.next()+" can't be fitted anywhere.");
            }

        }
    }
}

IF INTEGER TOO LONG ,ERROR COMES FOR ANYONE:

USE 'L' AT ENDING OF LONG.

HERE'S HOW IT IS: if(x>=-9223372036854775808L && x<=9223372036854775807L )System.out.println("* long");

AND UPVOTE IF IT HELPS YOU OUT.