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  4. Java Datatypes
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Java Datatypes

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1610 Discussions

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  • dorseymonica7
     + 7 comments

    This is a great exercise for understanding how data types work in Java, especially when it comes to choosing the right type for storing numeric values. Cricplus Pro

  • abderrahmaneida1
     + 0 comments
    import java.math.BigInteger;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        try (Scanner scanner = new Scanner(System.in)) {
            int t = scanner.nextInt();
            while (t-- > 0) {
                BigInteger n = scanner.nextBigInteger();
                if (n.bitLength() < Long.SIZE) {
                    System.out.println(n + " can be fitted in:");
                } else {
                    System.out.println(n + " can't be fitted anywhere.");
                    continue;
                }
                if (n.bitLength() < Byte.SIZE) {
                    System.out.println("* byte");
                }
                if (n.bitLength() < Short.SIZE) {
                    System.out.println("* short");
                }
                if (n.bitLength() < Integer.SIZE) {
                    System.out.println("* int");
                }
                if (n.bitLength() < Long.SIZE) {
                    System.out.println("* long");
                }
            }
        } catch (Exception e) {
            throw new RuntimeException(e);
        }
    }
}

  • naveenkumarsps21
     + 1 comment

    import java.util.; import java.io.;

    class Solution{ public static void main(String []argh) {

        Scanner sc = new Scanner(System.in);
    int t=sc.nextInt();

    for(int i=0;i<t;i++)
    {
        try
        {
            long x=sc.nextLong();
            System.out.println(x+" can be fitted in:");
            if(x>=-128 && x<=127)System.out.println("* byte");
            //Complete the code
            if(x>=-32768 && x<=32767)System.out.println("* short");
            if(x>=-2147483648 && x<=2147483647)System.out.println("* int");
            if(x>=-9223372036854775808L && x<=9223372036854775807L)System.out.println("* long");
        }
        catch(Exception e)
        {
            System.out.println(sc.next()+" can't be fitted anywhere.");
        } 
    }
}

    }

  • MariaaGray4
     + 0 comments

    The instructions for input and output are also practical, showing how to handle multiple test cases and check each primitive’s capacity. Andhra 365 Login

  • [deleted]     + 1 comment

    import java.util.; import java.io.;

    class Solution{ public static void main(String []argh) {

        Scanner sc = new Scanner(System.in);
    int t=sc.nextInt();

    for(int i=0;i<t;i++)
    {

        try
        {
            long x=sc.nextLong();
            System.out.println(x+" can be fitted in:");
            if(x>=-128 && x<=127)System.out.println("* byte");
            //Complete the code
            if((short) x == x)System.out.println("* short");
            if((int) x == x)System.out.println("* int");
            System.out.println("* long");
        }
        catch(Exception e)
        {
            System.out.println(sc.next()+" can't be fitted anywhere.");
        }

    }
}

    }

    My approach is simple. I tried to squeeze a number into smaller datatype. So, if the number stays same it means it fits in that datatype if does not fits it means the number is changed.