Don't use for loops like that! :-)

hi, how do you terminate taking the input from the console.. It kept asking, i print several runs...how do you exactly make the scan.hasNext() condition false through the console

for eg:hello 1 hello hi 2 hi how 3 how how are you

it still taking the input and i want to terminate here.

will you please explain
System.out.println(i + " " + scan.nextLine());

I am new to java

how to terminate the loop?

that's made wrong this is the right :

Scanner sc = new Scanner(System.in);

        while (sc.hasNextLine()) {
            int x=1;
            System.out.println(x++ + " " +sc.nextLine());


        }

Does it mean like returning TRUE only for any keyboard value?

Your for loop can be simplified:

// For loop 
public static void main(String[] args) {
   Scanner scan = new Scanner(System.in);
   for(int i = 1; scan.hasNext(); i++){
       System.out.println(i + " " + scan.nextLine());
   }
}

You don't have to use the == operator to compare with true since the hasNext method returns a boolean.

Thanq bro

vubon, Your loop is an infinte loop,I don't know how it works in Hackerrank, but it's not a correct way.

what is scan.hasnext ? scan is your scanner name ? but what is the meaning of this ?

Even if I dont put scan.hasNext == true; it works fine. Can you explain why?

Scanner scan = new Scanner(System.in);
        //for loop
        for(int i =1; scan.hasNext(); i++){
            System.out.println(i + " " + scan.nextLine());
        }

Worked for me too..

Scanner input = new Scanner(System.in);
        int counter = 1;
        String line = "";
        while(input.hasNext()) {
            line = String.format(counter+" "+input.nextLine());
            counter++;
            System.out.println(line);        
        }

nice for loop ;-)

thanks!

which part of this code reads from user input is it the "scan.hasNext()" or the "scan.nextLine()" ???

can you explain this code ???

Read some unknown n lines of input from stdin(System.in) where is this used in your program

Hey could you please help me with this problem... I am using a while loop just like you but in the output the Hello part is not being printed..

    this is my code-->
    Scanner sc=new Scanner(System.in);
    String s=sc.next();   
    int i=1;
    while(sc.hasNextLine())
    {     String s1=sc.nextLine();
          System.out.println(i+" "+s1);
          i++;
    }

    Expected Output-->
    1 Hello world
    2 I am a file
    3 Read me until end-of-file.

    My output-->
    1  world
    2 I am a file
    3 Read me until end-of-file.

here how does it scan the input because here it first check whether it has input or not and than it prints the output or can you please explain how does it take input?

How exactly is it accepting input?

in the for loop, no need for scan.hasNext() == true, just scan.hasNext, like in your while loop

Why "hasNext()", not "hasNextLine()"?

My solution with using "hasNextLine()" are working correctly or not?

public static void main(String[] args) {
    Scanner in = new Scanner(System.in);
    long i = 0;
    while ( in.hasNextLine() ){
        System.out.println(++i + " " + in.nextLine());
    }
    in.close();
}

the i++; has to be after the output println. Otherwise, its good.

This particular example is not assuming that the "end-of-file" string will come at the latest line, therefore this solution will fail.

At first hasNext() is pointing to wempty string so how it is running

That will give a timeout error

why we learn this? can you give me any example where this thing will be useful?

Thanks for providing the solution

Initially 'in' will be empty right?Then,how will 'in.hasNext()' return true?

Thanks bro

import java.io.; import java.util.; import java.text.; import java.math.; import java.util.regex.*;

public class Solution {

public static void main(String[] args) {
          Scanner sc=new Scanner( System.in);
    String a=sc.nextLine();
    String b=sc.nextLine();
    String c=sc.nextLine();
    for(int i=1; sc.hasNext(); i++)
    {
        System.out.println(i+" " +sc.nextLine());
    }
}

}

Sir, they said we have to take input. But you have written the code only for checking and printing. But where is the input that we should enter.

Initially 'sc' will be empty right?Then,how will 'sc.hasNext()' return true?

nice!

I Have this problem too.

i should start from 1, instead 0

for(int i=1; scan.hasNext()==true; i++){

   System.out.println(i + " " + scan.nextLine());

   if(scan.hasNext()==false) 
        System.exit(0);
        }


   #Generally System.exit(0) is used to terminate the JAVA Program

This work fine..............