What do you mean?

can you explain why ?

???

Ctrl-Z works for me. But there is a bug in Eclipse: you have to switch the view, then go back to the console and then you can enter Ctrl-Z.

read my answer on the top

It's equivalent to this code:

String line = scan.nextLine();
System.out.println(i + " " + line);

it prints the current i value. And the Double inverted commas work as giving space between the value of i and the value of the scan object value that has been read by the compiler entered by the user.

it prints number(i) plus space(" ") plus the next line

In Stdout first of all current value of i will be print than " " will genrate space and scan.nextLine() will print value read by compiler. For example if i=1 and complier reads input such as "Hello Eveyone !" so it will be printed like this: 1 Hello Eveyone !

When scan.hasNext() == false.

I had the very same problem. I didn´t had the idea to put scanner.hasNext()==true in the termination condition.

Scanner sc = new Scanner(System.in); int count=1; while (sc.hasNextLine()) { System.out.println(count++ + " " +sc.nextLine());

 }

@ohdoghdffdogdf, you need place int x=1 out of the while loop. Otherwise, it prints 1 everytime for each subsequent lines.

that is: each time when you do the loop, you re-initialize x to 1

int x=1; is use ouside the loop'

initialize x outside while loop man.

int x=1; while (sc.hasNextLine()) { System.out.println(x++ + " " +sc.nextLine()); }

But it is not passing all the testcases.

In fact, you can shorten it even further (at a potential loss of readability) by including the print statement within the for loop:

for(int i = 1; scan.hasNext(); System.out.println(i + " " + scan.nextLine()), i++);

It's not actually.When there is no more line of inputs the hasNext method returns false and the loop terminates.

That's it, scan is his scanner's name, that's the name he gave to the object created. Scanner x = new Scanner(System.in); ::: x is the scanner's name

Because, the for loop check if the condition is true but scan.hasNext() is already boolean.

• When scan.hasNext() return TRUE:
• TRUE == TRUE -> TRUE
• When scan.hasNext() return FALSE:
• FALSE == TRUE -> FALSE

So you see, it's not necesary compare with other boolean.

Other example: the method isEmpty(Returns true if this list contains no elements.), We will mostly need to know when the collection contains elements, so we use it this way:

if(!myCollection.isEmpty()){
    //do something with the elements...
}
//Or we can compare with false
if(myCollection.isEmpty()==false){
    //do something with the elements...
}

We simply deny it.

(Sorry my english)

scan.nextLine();

line 2: String s=sc.next(); //this scans for "Hello" thats why you are not getting it in the output, try removing it.

Write String s= sc.nextLine(); not sc.next();

sc.next(); ----> searches for the first space in the input sc.nextLine(); --> looks for the line change or \n in the input

while(scan.hasNext()) should be the line you use. Also, don't use the strings. The only time String should be in the code is the very beginning.

Scanner scan = new Scanner(System.in);

    int lineNum = 1;

    while(scan.hasNext())
    {
        System.out.println(lineNum + " " + scan.nextLine());
        lineNum++;

This was my code that I used, and it works flawlessly.

thanks bro

Read the println line you can see that in.nextline() this is were input is taken.

Instead of storing the input in a seperate string and printing the string...

String input = scanner.nextLine();
System.out.println(input);

I instead just print out the input

System.out.println(scanner.nextLine());

Not sure if that was your question. If you are confused as to how it knows when to stop looking for input, the statement:

while(scanner.hasNext()){
    //Code here
}

Will continue looping over and over again until scanner.hasNext() returns false, meaning there is nothing left to read from the Scanner.