Suggestion: Make the fourth testcase less strict. I had my catch outting...
java.util.InputMismatchException: For input string: "2147483648"
When it expected...
java.util.InputMismatchException
I simply made another catch for that specific exception and output "java.util.InputMismatchException" directy to work around it but I feel like that shouldn't be necessary. Unless simply printing out the Exception directly is the wrong way to go about it?

Again a great example of how bad the test cases are written. Any professional would have caught the exceptions together and logged / souted them in a uniform way like this:

try (Scanner scanner = new Scanner(System.in)) {
	System.out.println(scanner.nextInt()/scanner.nextInt());
} catch (ArithmeticException | InputMismatchException ex) {
	System.out.println(ex);
} 

This is best practise for any team I worked with and definitely the cleanest way to solve this. But thanks to the nitpicking test cases, beginners learn to catch exceptions in an utterly bloated way:

try (Scanner scanner = new Scanner(System.in)) {
	System.out.println(scanner.nextInt()/scanner.nextInt());
} catch (ArithmeticException aex) {
	System.out.println(aex);
} catch (InputMismatchException imex) {
	System.out.println(imex.getClass().getName());
}

This worked for me:

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        try{
            int x=sc.nextInt();
            int y=sc.nextInt();
            int z=x/y;
            System.out.println(z);
        }catch(InputMismatchException ime){
            System.out.println(ime.getClass().getName());
        }catch(ArithmeticException ae){
            System.out.println(ae.getClass().getName()+": "+ae.getMessage());
        }catch(Exception i){
            System.out.println(i.getMessage());

        }
    }
}

Java solution - passes 100% of test cases

From my HackerRank solutions.

import java.util.Scanner;
import java.util.InputMismatchException;

public class Solution {
    public static void main(String[] args) {
    	Scanner scan = new Scanner(System.in);
        try {
            int x = scan.nextInt();
            int y = scan.nextInt();
            System.out.println(x/y);
        } catch (InputMismatchException e) {
            System.out.println(e.getClass().getName());
        } catch (ArithmeticException e) {
            System.out.println(e.getClass().getName() + ": / by zero");
        }
    }
}

Let me know if you have any questions.