if(n%2==1 || (n>=6 && n <= 20)){
  ans = "Weird";
}else{
  ans = "Not Weird";
}

or even...

ans = "";
if (n%2 == 0 && (n>20 || n < 6) { ans += "Not "; }
ans += "Weird";

Single line solution, just for fun, and cuz I love the ternery operator ;-) (passed all 7 TC's)...

System.out.println((n%2==1 || (n>=6 && n<=20)) ? "Weird" : "Not Weird");

can anyone tell me why

scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

this thing is written what exactly is its meaning I am new to programming

Is this correct pros?

if(n>=2 && n<=5)ans = "Not Weird"; else if(n>=6 && n<=20)ans = "Weird"; else if(n>20 && n<=100)ans = "Not Weird";

import java.io.; import java.math.; import java.security.; import java.text.; import java.util.; import java.util.concurrent.; import java.util.regex.*;

public class Solution {

private static final Scanner scanner = new Scanner(System.in);
public static void main(String[] args) {
    int N = scanner.nextInt();
    scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
    if(N % 2 !=0){
        System.out.println("Weird");
    }
    else{
    if(N >=2 && N <=5){
    System.out.println("Not Weird");
    }
    else if (N >=6 && N <=20){
        System.out.println("Weird");
    }
    else if (N > 20)
    {
        System.out.println("Not Weird");
    }
    }
    scanner.close();
}

}