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inanutshellus 5 years ago+ 0 comments

if(n%2==1 || (n>=6 && n <= 20)){
  ans = "Weird";
}else{
  ans = "Not Weird";
}

or even...

ans = "";
if (n%2 == 0 && (n>20 || n < 6) { ans += "Not "; }
ans += "Weird";

SeanRMunoz 4 years ago+ 0 comments

Single line solution, just for fun, and cuz I love the ternery operator ;-) (passed all 7 TC's)...

System.out.println((n%2==1 || (n>=6 && n<=20)) ? "Weird" : "Not Weird");

scm89247 6 months ago+ 0 comments

can anyone tell me why

scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

this thing is written what exactly is its meaning I am new to programming

rajarubancr 4 years ago+ 0 comments

Is this correct pros?

if(n>=2 && n<=5)ans = "Not Weird"; else if(n>=6 && n<=20)ans = "Weird"; else if(n>20 && n<=100)ans = "Not Weird";

rcgonzalezf 4 years ago+ 0 comments

String ans="Weird";
if( n%2==0 && !(n >= 6 && n <= 20)){
    ans = "Not " + ans;
}
System.out.println(ans);