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  2. Java
  3. Object Oriented Programming
  4. Java Interface
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Java Interface

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  • julian_n_robbins
     + 0 comments

    You can optimize by going only up to sqrt(n) and adding both the factors at once (similar principal when looking for Prime numbers).

        public int divisor_sum(int n) {
        if(n==1) return 1;
        int sum=0;
        for(int i=1; i * i <= n; i++) {
            if(n%i==0) {
                sum += i;
                sum += n/i; //other factor of a * b = n
            }
        }
        return sum;
    }

  • frochaolivera18
     + 0 comments

    This website is shit bro.

  • yashdeora98294
     + 0 comments

    Here is java Interface solution - https://programmingoneonone.com/hackerrank-java-interface-problem-solution.html

  • r3mdh066
     + 0 comments

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  • sathish0723
     + 0 comments
    import java.util.*;

interface commonDevison {
    int divisor(int n);
    
    
}

class calculator implements commonDevison{
    public int divisor(int n){
        int sum = 0;
        
        for(int i=1;i<=n;i++){
            if(n%i==0){
                sum+=i;
            }
        }
        return sum;
    }
}

public class Solution {

    public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
       Scanner input = new Scanner(System.in);
       int n = input.nextInt();
       
       commonDevison calculator = new calculator(); 
       System.out.println("I implemented: AdvancedArithmetic");
       System.out.println(calculator.divisor(n));
    }
}