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  1. Prepare
  2. Java
  3. Object Oriented Programming
  4. Java Iterator
  5. Discussions

Java Iterator

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217 Discussions

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  • jasvan35sundar
     + 0 comments

    import java.util.*; public class Main{

    static Iterator func(ArrayList mylist){ Iterator it=mylist.iterator(); while(it.hasNext()){ Object element = it.next(); if(element instanceof String) if(element.equals("###"))

         //Hints: use instanceof operator

        break;
    }
  return it;

    } @SuppressWarnings({ "unchecked" }) public static void main(String []args){ ArrayList mylist = new ArrayList(); Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int m = sc.nextInt(); for(int i = 0;i 

      mylist.add("###");
  for(int i=0;i<m;i++){
     mylist.add(sc.next());
  }

  Iterator it=func(mylist);
  while(it.hasNext()){
     Object element = it.next();
     System.out.println((String)element);
  }

    } }

  • yury_a_kulikou
     + 0 comments

    if("###".equals(it.next())) break;

  • yashdeora98294
     + 0 comments

    Here is Java Iterator solution - https://programmingoneonone.com/hackerrank-java-iterator-problem-solution.html

  • serg_aleshchenko
     + 0 comments
    static Iterator func(ArrayList mylist){
      Iterator it=mylist.iterator();
      while(it.hasNext()){
         Object element = it.next();
         if(element instanceof String)
            if(element.equals("###"))
			break;
		 }
     return it;
      
   }

  • devashis_k2002
     + 0 comments
    public class Solution {
    @SuppressWarnings({ "unchecked", "rawtypes" })
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int numLenght = scanner.nextInt();
        int strLenght = scanner.nextInt();
        ArrayList list = new ArrayList();
        for (int i = 0; i < numLenght; i++) {
            list.add(scanner.nextInt());
        }
        list.add("###");
        for (int i = 0; i < strLenght; i++) {
            list.add(scanner.next());
        }
        list.stream().filter(s -> s instanceof String && ((String) s).matches("[a-zA-Z]+")).forEach(System.out::println);
        scanner.close();
    }
}