Seems like "###" should cause a problem.

Unfortunately, it was hard to understand and I had to resort to evil AI.

Em...now I know that we loop through, and the "Iterator" objects get consumed, much like with a Scanner.

That's really where I ended up getting quite lost and feeling like my time was being wasted (as AI will), because I suppose that using a return inside an iterator is unusual, and I couldn't see such a weird implementation on YouTube examples. So why did HackerRank propose such a confusing use of Iterator to get used to this? F***** if I know. That will teach me to try these without reading about them on Baeldung first.

   static Iterator func(ArrayList mylist){
      Iterator it=mylist.iterator();
      while(it.hasNext()){
         Object element = it.next();
         if(element instanceof String) 
			break;
		}
      return it;
      
   }

This is a good demonstration of how Java’s Iterator works with an ArrayList. Mahadev Bookie Number

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Those who thought (element instanceof Main); one minute of silence (R.I.P)....

import java.util.*; public class Main{

static Iterator func(ArrayList mylist){ Iterator it=mylist.iterator(); while(it.hasNext()){ Object element = it.next(); if(element instanceof String) if(element.equals("###"))

     //Hints: use instanceof operator

        break;
    }
  return it;

} @SuppressWarnings({ "unchecked" }) public static void main(String []args){ ArrayList mylist = new ArrayList(); Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int m = sc.nextInt(); for(int i = 0;i

  mylist.add("###");
  for(int i=0;i<m;i++){
     mylist.add(sc.next());
  }

  Iterator it=func(mylist);
  while(it.hasNext()){
     Object element = it.next();
     System.out.println((String)element);
  }

} }