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  1. Practice
  2. Java
  3. Introduction
  4. Java Loops II
  5. Discussions

Java Loops II

  • rathoreabhi1990 + 6 comments

    It will not work. First line i.e. int tempAnswer = A; It will fail.

    • meet_alexmac + 0 comments
      [deleted]
    • chaitanya492 + 3 comments

      yes, u are right,, but what is the reason behind it??

      • Zeeshan1996 + 0 comments
        [deleted]
      • geo_sam_ca + 1 comment

        It should be an "a".

        • Mitprajapati + 2 comments

          int tempAnswer = 0; for (int j = 0; j < loop; j++) { tempAnswer += (Math.pow(2, j) * b); System.out.print(tempAnswer + a + " "); }

          • rajmetre92 + 0 comments

            nice

          • ayu_agr2011 + 1 comment

            when i write tempAnswer = tempAnswer + (Math.pow(2,j)*b); it gives an error of loss of precision. Can you please explain me why is it so?

            • lakshmi_bhavani1 + 1 comment

              pow() gives a double value,but you are using an integer so the precision is lost..Type cast the pow() function to integer . You will get it done.

              • ritabandas2000 + 0 comments

                In case you haven't noticed, first you need to take all the inputs and then output according to each of them. Not, give the output after every, input.

      • sherzodkh + 2 comments
        [deleted]
        • goyallovish52 + 1 comment

          what is the need of taking two seperate variables: storage and formula

        • 16bce169 + 2 comments

          If you use "println" then every number will be printed in next line..........

          public static void main(String []argh){ Scanner in = new Scanner(System.in); int t=in.nextInt(); for(int i=0;i 

                  int sum=0;
        sum += a + (pow(2,0)*b);
        System.out.print(sum+" ");
        for(int j=1;j<n;j++)
        {
            sum = sum + (b*pow(2,j));
            System.out.print(sum+" ");
        }
        System.out.println();
        sum=0;


    }
    in.close();
}
static int pow(int a,int b)
{
    if(b>0)
    {
        return(a*pow(a,b-1));
    }
    else
    {
        return 1;
    }
}
          • TyagiLalit + 1 comment

            VIT VIT VIT

            • mech_engg + 0 comments

              Lol

          • 16JG1A1242IT + 0 comments

            *then y did i get wrong output here? *

            class Solution{ public static void main(String []argh){ Scanner in = new Scanner(System.in); int t=in.nextInt(); int s=0; int j; for(int i=0;i

    • piyushmanglani08 + 0 comments

      it will work and it works properly dude.

    • LALIT4960 + 3 comments
      int tempAnswer = A;
for (int j = 0; j < loop; j++) {
        if (j == 0)
            tempAnswer += a;
    tempAnswer += (int) (Math.pow(2.0, j) * B);
    System.out.print(tempAnswer + " ");
}



    This will work as we need to add a in the first instance only
      • A_Band + 0 comments

        YOur Code is aWesOmE.

      • pprathameshmore + 0 comments

        Your code is helpful!

      • chainani_navin97 + 1 comment

        bro u logic is wrong

        • satyam_pandey571 + 0 comments

          how??..can u explain me?

    • Etcetra + 0 comments

      take in small case alphabets i.e. "a"

    • itikalamadhavi01 + 0 comments
      [deleted]