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This solution is what I considered at first too, but if you do this, you will end with a trailing space. It's better to print hte first number (a + 1 * b) and then print " " + newAnswers in your loop.
class Solution{
public static void main(String []argh){
Scanner in = new Scanner(System.in);
int t=in.nextInt();
for(int i=0;i
public static void doJob(int a, int b, int n){
int result=0;
result = a+result;
for (int i = 0 ;i<n;i++){
result =result + (int)Math.pow(2, i)*b;
System.out.print(result + " ");
}
System.out.println();
}
to find a power of value of the result variable using
Math.pow()
which returns a double value as a library method. You thus need to cast it to an int in order for it to work/compile. You will get a casting error otherwise.
Good solution.But inorder to run another test case make sure to add result = 0; after System.out.println(); otherwise it will take previous result value for another test case.
Java Loops II
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This solution is what I considered at first too, but if you do this, you will end with a trailing space. It's better to print hte first number (a + 1 * b) and then print " " + newAnswers in your loop.
This one works as it should I guess:
import java.util.; import java.io.;
class Solution{ public static void main(String []argh){ Scanner in = new Scanner(System.in); int t=in.nextInt(); for(int i=0;i
}
why do we need int before Math.pow
You are using
to find a power of value of the result variable using
which returns a double value as a library method. You thus need to cast it to an int in order for it to work/compile. You will get a casting error otherwise.
pow() takes both of its arguments as double.
pow() results in double
That implies type casting
type casting
that int is needed for type casting or for converting double data type to int type , as we know that Math funcction is of double..
Good solution.But inorder to run another test case make sure to add result = 0; after System.out.println(); otherwise it will take previous result value for another test case.
why are you creating another method? Why not do the same thing in main method?
it fails not work
According to me best solution
*then y did i get wrong output here? *
class Solution{ public static void main(String []argh){ Scanner in = new Scanner(System.in); int t=in.nextInt(); int s=0; int j; for(int i=0;i
You can use the .trim() method on your output string to remove the trailing space:
int runningTotal = a; String outputString = ""; int multiplier = 1;
for(int count = 1; count <= n; count++) { runningTotal += multiplier * b; outputString += runningTotal + " "; multiplier *= 2; }
System.out.println(outputString.trim());
It solves the problem of a^(count-1). Thank you.