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(1<<h) Starts with 2 to the zeroth power, a binary 1, Shifts the number to the left by h binary bits, e.g 00000001 in binary left shift 1 becomes 00000010, left shift 2 becomes 00000100.

Left-shifting a binary number by 1 bit position multiplies that number by 2. Left-shifting by 2 multiplies by 2^2. Left-shifting by 3 multiplies by 2^3, etc.

## Java Loops II

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I didn't need to call the Math.pow() function.

I used

what does this line(

result += (1<< h) * b) do? what is the role of<<operator?a += b; is the same as a = a + b;

(1<<h) Starts with 2 to the zeroth power, a binary 1, Shifts the number to the left by h binary bits, e.g 00000001 in binary left shift 1 becomes 00000010, left shift 2 becomes 00000100.

Left-shifting a binary number by 1 bit position multiplies that number by 2. Left-shifting by 2 multiplies by 2^2. Left-shifting by 3 multiplies by 2^3, etc.

thankyou..

nice idea with the binary shift!

for(int i=0;i

Should be h<=x+1