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Math.pow() is a function that is provided to us by Java. Here, it takes 2 parameters. When I pass in 2 and j, it does exponentiation (known as "power") as 2 to the j-th power. For example, Math.pow(3,5) = 3 * 3 * 3 * 3 * 3.
Also, Math.pow() returns a double instead of an int. We "cast" it to an integer by putting
(int)
in front of it. We cast our result since a is an integer type and we can only assign an int type to it.
class Solution{
public static void main(String []argh){
Scanner in = new Scanner(System.in);
int t=in.nextInt();
for(int i=0;i<t;i++){
int a = in.nextInt();
int b = in.nextInt();
int n = in.nextInt();
for (int j = 0; j < n; j++) {
int c = a + b * (int) Math.pow(2, j);
System.out.print(a + " ");
a = c;
}
System.out.println();
}
in.close();
}
}
Java Loops II
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Can you please explain what does this line do? a += b * (int) Math.pow(2, j);
is shorthand for
Math.pow() is a function that is provided to us by Java. Here, it takes 2 parameters. When I pass in 2 and j, it does exponentiation (known as "power") as 2 to the j-th power. For example, Math.pow(3,5) = 3 * 3 * 3 * 3 * 3.
Also, Math.pow() returns a double instead of an int. We "cast" it to an integer by putting
in front of it. We cast our result since a is an integer type and we can only assign an int type to it.
Hope this helps.
HackerRank solutions.
Thank you very much for explaining me.
what's wrong with this? can you please tell me
I think the values for "a" and "c" are incorrect inside the inner for loop.
where the value of t is used ?what is neccesary of it in this code....
t is number of test cases
Great explanation. Thank you so much.
The value of 'b x 2^j' gets added to 'a' in that expression. It is like 'a = a + (b x 2^j)'. Hope this helps.