import java.util.Scanner;

public class Solution {

public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        System.out.println("================================");
        for(int i=0;i<3;i++)
        {
            String s1=sc.next();
            int x=sc.nextInt();
            System.out.printf("%-15s%03d%n", s1, x);
        }
        System.out.println("================================");

}

}

public class Test {
	public static void main(String[]args) {
		Scanner sc=new Scanner(System.in);
        System.out.println("================================");

		for(int i=0; i<3; i++) {
			String sl=sc.next();
			int x = sc.nextInt();
			
			
			System.out.printf("%-15s%03d%n", sl, x);
		
		}
        System.out.println("================================");

		
		
		
		
	}
}

As a begginer I dont expect other people to come up with a solution in less than 20 mins.

As a begginer it took me around 2 hours looking at countless youtube videos about this before finnaly getting to this- https://www.youtube.com/watch?v=moQ3Kr8ouiU

this dude has done a 12 part series all about printf statements in java! By far the there is out there! You can come here and copy/paste the code to congratulate yourself or you can look up all 12 videos of this guy and get FULL understanding of printf in JAVA!

Do yourself a favour and watch his videos! 'printf' is much larger than you realise!

I kept getting it wrong and 4 hours later I gave up and came to discussions only to realise my code is 99% right. One this that wasnt right was %n which is bassically new line for printf, could have saved my 1 and a half hour by being more careful myself!

here's my code and a good refrence at the bottom

import java.util.Scanner;

public class Solution {

public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
                System.out.println("================================");
        for(int i=0;i<3;i++)
        {
            String s1=sc.next();
            int x=sc.nextInt();

            if(s1.length() > 10){
                s1 = s1.substring(0, 10);
            }


           System.out.printf("%-15s%03d%n", s1, x);
        }
        System.out.println("================================");

}
}

http://www.homeandlearn.co.uk/java/java_formatted_strings.html

import java.util.Scanner;

public class Solution {

public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        System.out.println("================================");
        for(int i=0;i<3;i++)
        {
            String s1=sc.next();
            int x=sc.nextInt();
            for (int j=s1.length();j<15;j++){
                s1 += " ";
            }
            System.out.println(s1 + String.format("%03d", x));
        }
        System.out.println("================================");

}

}

Java solution

• The "-" is used to left indent
• The "15" makes the String's minimum length it takes up be 15
• The "s" (which is a few characters after %) will be substituted by our String
• The 0 pads our integer with 0s on the left
• The 3 makes our integer be a minimum length of 3

import java.util.Scanner;

public class Solution {

    public static void main(String[] args) {
            Scanner sc = new Scanner(System.in);
            System.out.println("================================");
            for (int i = 0; i<3; i++) {
                String s1 = sc.next();
                int x = sc.nextInt();
                System.out.format("%-15s%03d%n", s1, x);
            }
            System.out.println("================================");
    }
}

From my HackerRank Java solutions.