MalazAlamir import java.util.Scanner;
public class Solution {
public static void main(String[] args) { Scanner sc=new Scanner(System.in); System.out.println("================================"); for(int i=0;i<3;i++) { String s1=sc.next(); int x=sc.nextInt(); System.out.printf("%-15s%03d%n", s1, x); } System.out.println("================================"); }}
akomcl01 can you please explain this line. thanks"("%-15s%03d%n", s1, x);"
thens ("%-15s%03d%n", s1, x) % : used as a formatter. '-' : minus sign used for left indentation of the string. 15s : here 15 denotes the string's minimum field width 15. '0' : pads the extra 0s in the integer. 3d : here 3 denotes integer's minimum field width 3. %n : prints the new line.
Hope, this helps!
romanshyadav if our first input integer is 2384754 or second 5 so how we add 000000 to make this like 0000005.
Ragavan1989 %07d will add 000000 followed by 5
JKDos common sense. Haha
vinaymaduri123 hohoho
KattuPoochi thank you soooooo much:)
nrnaveenkmr anne kattupoochi vanakam anne
rithikacariappa They have asked for only numbers between 0 and 999 here so the %03d padding is enough here. If you need more digits in your number, then you give padding as necessary; in your case, %07d.
sanjeevsingh Awesome Explanation... I have used for the first time..
RISHAV_SHARMA mee too
Srpolash16 same here
manojingalagi199 same here thank you
ud5162 I have also
abhicuel068 same here, formatted outputs is a new terminology to me
shikha_sinha06 me too
smadden03 same as well
brailemcwaine same too
saisushvitha yes getting to know new things tq. :)
sinha_amrit093 Thank you!
rawheat_gulati lets keep it going till it croses the page lol XD
manojmk95 haha
abhinav_masa0 haha me too
anukarsh_007 [deleted]
rustyelectron hahaha
santosh_mummidi I never knew printf can be used in Java also!
hivex201 [deleted]hm9himanshu Samehere! lol
trxbach LOL
avijha LOL
neetujangra20 intersting:)
Rashad_Amir someone else? hahaha
MQ_T_L This really helps a lot, thank you! And guys... we're pretty far out right
ubfacility not there yet... :)
TylerRodriguez Same
surendarlal69 Thank you...
nikeshprasad9 New for me too, it was great learning about this!!
huntdea000 boonk gang
rama_bena what happen with the page
madhav5589 [deleted]srisachin093 Does it works in IDE? Have you tried anytime?
sgnk93 you can also use \n instead of %n for printing a newline. Thanks for your help.
ButtahNBred It's important to note that the '\n' newline character also adds a linefeed at the end. If you do not want the linefeed you should use "%n".
--The Java Tutorial: Formatting
somisingh what is line feed ?
BikramBitu line feed mean. to add a new line In Java, \r is always carriage return, and \n is line feed.
daiict_201712031 Why \n and %n both works for this program ? Can you give an example which helps to understand the difference between them ?
upendra28 %n is portable between various platforms, the value emmitted from %n will suits underlaying platform, where as value emmitted by \n is same for all the paltforms.
pauluci yeah, i've used \n instead of %n and both work fine. Thanks.
thien_vuhoang97 how about \t ??
anupma1490yadav \t is for vertical spacing
shashank21jHackerRank Admin \t is tab
shankyorbis \t is horizontal tab that is equivalent to 4 spaces at a go
harisivaram369 i think tab gives only 3 spaces
falturba tab is a tab. It could be presented as 3, 4 or more spaces. Depends on the text editor, browser, etc. But most cases it's 4 spaces
Naibeck This is what official documentation saids: A new line character appropriate to the platform running the application. You should always use %n, rather than \n.
rahulkumardubey thank you
satyasri12511001 thank you so much
satyasri12511001 thank you so much
sdesai11 It helped a lot! Nice explanation.
Krishnaveni_DG Nice explanation. Thank You.
S_hivam what we will use for right indentation .?
mailmesindhuja14 thank you ! i learnt from u!
sriarul1993 Good Explanation
LosersNeverWin that was cool man using printf in java....
manojingalagi199 Thank you for the explanation.
maddysingh here '-' minus sign is used for left indentation... Can we use '+' for Right indentation if not then what should we do for Right indendation???
sayantankundu93 just dont use the '-' sign..
svlunawat11 what is left and right indentation?
bharatim_smile by default it is right
deekshith565 Why it is not working if I use println for this statement?
AdiDutta_69 The Objective of the question is to use 'printf' statements. So during code testing, the JUnit Test looks only for the 'printf' statement.
rsdp016 how can we print justified output using "println"
isurumaduranga94 thank you very much :)
viswaaditya007 What does s and d indicate?
NikhilGandudi s indicates string and d indicates integer.
vermasahil269 gud explaination i have use it first time
rishabh0_9 why i can't go to this way println("%-15s%03d",s1,x)
here i am using println intead of %n for new line
Sumeet_Kale_8407 thanx!
SuprabhaS 15 denotes the string's minimum field width 15. I didnt get this will you plz explain
151FA04046 excellent explanation..
wowlad what is x used for
smaita thanks!
kotjag Great explanation!! Thanks :)
hoodaajay169 new thing to be learnt
amirmahdi76 What is a formatter? and why do we have 3 formatters but only 2 variables (i.e s1 , x)?
thanks
sravaniteja explain please?
developerjake The formatter is a placeholder.
If you imagine a coaster (as in the little bit of card where you put your cup when you're drinking something...) That's comparable to a formatter, in the sense that it shows the place you should put something.
There are only two formatters here:
"%-15s%03d%n"
The one that you think is the third:%nactually represents a linebreak (like hitting Return on your keyboard while typing a sentence).%s = String // a string goes here %d = int (digit) // an int goes here %f = float // a float goes here
Let's look at the whole statement:
("%-15s%03d%n", s1, x)
The two formatters are:
%-15swhich is where the variables1(a String) is placed.
%03dwhich is where the variablex(an int) is placed.The other parts of those formatters mean different things...
The
-15part means that:
-: whens1is put into this spot, keep it to the left side.
15: make sure it takes up 15 spaces.
EXAMPLE ifs1 = hithen it will produce:"hi " // Note that the string is 15 characters long
The
03part means that whenxis put into this spot:
3: it must take up three spaces.
0: any spaces it doesn't use are to be filled with0's.
N.B. The default padder is whitespace" "if0is not used.
EXAMPLE
ifx = 70then it will produce:"070" // The result is 3 characters long, with a '0' filling the unused space
Time to watch some tutorial videos I guess! Good luck.
kalyankumar11311 superb expelnation man
nobabsifat [deleted]
charan_sai clear explanation :)
ambika17694 Awesome Explanation...
monal_stp thank you for this awesome explanation
harisivaram369 but how the spaces between string and integer are denoted in program
Evea_Zerin Did you get an answer? I had the same question about the space in the centre
harisivaram369 ================================ java 100 cpp 065
python 050
sulan1994 Can you tell me please, where i can find some serious TuT Videos? I would love to learn this kind of things. Between, thanks for the clear explanation!
karibayasmin Awesome explanation Bro!!
daksha_kanet you cleared my doubt, thank you
akarws Thank you for the clear explanation!
mm989 good explanations learned something new
asheeshkumar96 well explained
pritamvalentine1 what is the use of % ?
Evea_Zerin Default padder " " will always be in the middle? Keeping the string and int on the ends.
ramadvija555 nice explanation
deshpandeabhi_10 Thanks for the explanation ...
yaliniyalu nice explanation
durgabhavani1127 it is very useful and clearly explained @thens
kartikrkarpate plz can u give some alternative solution for this
mohammedsaleem71 Thanks buddy
diticuo062 It's interesting!
kashyapjv what is the difference between println(or print) and printf??
shikhar18feb why you used print f instead of printrline
mar87 Thanks!! for your explanation about this exercise
rvsrishi thnks
neerugattiraju Thanks for the Clarification..!
tharun_eniyan which sign is used for right indentation of the string?
snehavidhyashek1 %-15s --> for string with left indentation with length 15 %03d --> for integer with length and padded with zero
harhacker [deleted]
bhaviktalesra Hi, Thanks for this.
If I need to '1' instead of '0' for integer, then how to modify this as
("%-15s%13d%n", s1, x) is not producing desired o/p.
Would appreciate if you may help with this.
harreeshpl can u do it with string concatination
harreeshpl can u do it using string concatination
t_tejcharan Good Explanation
lsfernandes92 Awesome, but java turn this really ugly, for god....
rkrishnaranjani1 thank you so much..
mayankshekhar03 great!
lochek_alon Gosh, I was trying to use loops for it to find out how many spaces I need to add, and this turns out to be such a simple thing....
djdiwakar_joshi1 Thanx for such a pleasant explanation.
chaitanya_vcs22 thank u
pankajgr7 thanks nice explanation
tiwarisiddharth3 I dont have the words to your effort to make us understand the meaning of that line...
supriyams1999 thank you ,i'm using this first time
prasanna_lakshm1 Fantastic!!
swarupasolanker if we integer is 5 and we used %-08s then o/p will be 00000005
vrushalipunde great!!
rectangle So "%n" can also be used to print new line, instead of "\n". Thank you for the explanation.
Flash_AkS Thank You
somupanda321 great:))
akajithkumar9700 super
hanijoshi99 thk s
bhushanjainabc thank you so much sir
bhushanjainabc Sir, if i forgot these code then you have any other example to solve this condition?
abhishekkvs1000 first time i see this type of concept
abhishekkvs1000 nice sir
sakilamnagasai super explanation
chetan27june why u are using , insteadof java uses + operator.please explain.
business_aziz101 why System.out.printf not System.out.println
sagardgoswami printf means printing with formatiing. While println means printing something in a specific line.
Printing with printf will end in same line, while println will take you to next line after the printing is done.
Hope that helps....
pramjee007 Thank You Sagar
vmande thanks
imabhiraj Thanks man
heenavasdanihun1 thanks
cian_j_mcintyre I don't know why this has been downvoted so much. It's a very valid question and I'm glad you asked it.
inoti Cool
amtkumar Cant we add space between %-15s & %03d
bala080798 thank you so much
sanyuktaagrawal1 - is used for left justification of string. 15s is used for 15 char length of string. 03d id used for max three digit length. visit https://docs.oracle.com/javase/tutorial/java/data/numberformat.html for more help
davijack well done
Hari_MBIH I am getting this error. error: no suitable method found for println(String,String,int)
wahadat I guess you have forgotten to write String.format and directly passing the strings and integers in println method.
surekhajadhwani The method should be printf and not println.
JKDos Maybe I'm thinking wrong, but if the string is too long (i.e "0123456789ABCDEF" )
You get
================================ Test 001 0123456789ABCDEF055 Example 349 ================================
sagardgoswami It mentions that input string must be 15 characters or less.
ajitexl1996 System.out.printf("%-15s%03d%n", s1, x);
printf meanssystem.out.print or println i know but printf i can't please explain
JKDos the "f" in printf stands for "Format" if I'm not mistaken.
printf is an avanced version of print. It allows you to not only print, but format it aswell. This example alone shows some nifty tricks. Some others would be formatting the decimals.
If you have a decimal of 5.243012 and you only wanted the first 3 places, you can use
System.out.printf("You Decimal Number is %.3f",myDecimal);
%f means print a float/double and use 3 decimal places.
the .3 means to print upto the third decimal (Thousandths)
when you pass variables to your printf command, besure to passthem in the order called.
EXAMPLESystem.out.printf("Hello %s, my name is %s. I am %d years old, and you are %d years old",yourName,myName,myAge,yourAge);
As you go on, you want to stop use System.out.print and move onto uses System.out.printf when you're printing data to the screen.You won't need to worry about println because adding a \n to your ptintf will add a line whereever the \n is placed.
clpagedev This comment saved my bacon, and allowed me to fully grasp the concept. Especially the simplification of the last example... btw I had to spell this out for me:
%d = int %s = String %f = float
prachi_1312 [deleted]
sidhs5695 can u plz tell what is this called basically and where can i learn this
kaju_kuwar how to get an outout 111115 for input 5?? instead of paddin zero can we add any other no.s ?
krishthiru ohhh i cccc
namila007 wow this code is really simple one, i did this but it went for so loong code :(
Barinder13 Thanks
rafly_hernandes may i know , knapa There should be a "code" , but when the code is not wearing , did not find the right
purohitjay19 first time saw this type of formatte .. thanks
RISHAV_SHARMA koi ni sab chalta h :)
arvind005 great explanation!!!
ramprasathrp Thanks you soo much for this code.
Please find the below link for your quick concept reference https://www.youtube.com/watch?v=Dj0oVoFkY1I
purvak191 this link is helpful.. thanks
rayhimanshu8 you can also use format------ System.out.format("%-15s%03d%n", s1, x);
Rijndael [deleted]minhvqse61021 thank u so much
ankit15120 After a sc.nextInt(); Statement when again for loop runs the first statement is reading a string So is it not possible that it will read an empty string? As we have heard that after reading int we should clear buffer or use empty sc.nextLine(); command. Please make me clear about why we do not need to clear buffer here? Thanks! your effort is appreciated.
Venkat30119 [deleted]
harshat We are using 's' and 'd' for string and int data types respectively, if I'm not wrong. Similarly, what should we use if we want to format other data types such a double, float, char etc.
tanphat3198 love this
Inherited_Geek See this link for explanation: http://www.homeandlearn.co.uk/java/java_formatted_strings.html
Jitesh_1798 can u plz explain how this loop is working??????
bhavya97 I know String s1=sc.next(); was already written in the code, but can we use nextLine() instead of next() ?
pallavisunbeam11 nice solution. But I think it could be explained in a better way.
navinck62846 Nice explaination!!!
vijaya268 pls tell me the meaning of this statement ** System.out.printf("%-15s%03d%n", s1, x);**
DanDrachenberg Had to change %-15 to %-14, otherwise the Test Case won´t let me pass. Oddly enough it still looks like i have one space too much on the Output Field.
Anne_P [deleted]
mehadikuet2013 Awasam... (y) Learn a new thing.. :)
gursimran16 what is mean of printf
System.out.printf("%-15s%03d%n", s1, x);sinha_amrit093 ("%-15s%03d%n", s1, x) % : used as a formatter. '-' : minus sign used for left indentation of the string. 15s : here 15 denotes the string's minimum field width 15. '0' : pads the extra 0s in the integer. 3d : here 3 denotes integer's minimum field width 3. %n : prints the new line. Hope, this helps!
v_ramkumar3197 yeah it helps
Purvi_ simply copied from the editorial @MalazAlamir
sagar10451 in the for loop we just run the loop where do those value get stored ? like in c we have array to store but here we dont have array so where do we store the 3 values?
sharmasanjeev681 why %03d works but %3d does not ? whats the difference ?
developerjake If you put the 0 in, it pads with
0s. If you don't put it in, it defaults to padding with whitespace.
kowcika why u use printf instead of println
sinha_amrit093 Its more of a convenience actually. Println prints on the line and automatically shifts to the next line. Hence saving us the "/n" notation after printing anything--which we need to use when we use printf(). So you can use anything :)
saisreeharshap what if we need right indentation?
sushmadasini For this same code, i got this run time error:
Exception in thread "main" java.util.InputMismatchException at java.util.Scanner.throwFor(Scanner.java:909) at java.util.Scanner.next(Scanner.java:1530) at java.util.Scanner.nextInt(Scanner.java:2160) at java.util.Scanner.nextInt(Scanner.java:2119) at Solution.main(Solution.java:10)
nikhilshrivastav I am getting the same
shadrak_98 it giving me an error . It says no suitable meth0d found for println(string,string,int)
aganga555 why you use printf insted of println
josef_ibrahim Great explination! Why doesn't that work with println instead of of printf?
bmk9727 but in the java what's meaning of printf(""); ???
winstone What if instead of adding zeroes, i wanted to add ones? Would the code then be %-15s%13d%n?
matsuo thank you
fav_ramkumar any other way to solve this? Please
emrullah_buke Thank you dude, thats really good :D
shraiysh How to get the indent to right? Or to the center?
surakshachindi i dint get y printf
poornima555 Does the formatted o/p works only with printf? How about System.out.print?
arunkumar20 I never knew there was a method for formatting output before. Good Explanation.
NickWhoCodes What does it mean for padding to be left-justified? My intuition (which is wrong) makes me think that adding blanks to the right of the word (until a length of 15) would be "right-justified".
sumitpanday125 this isn't working in mine only printing "==================" that's it.
rajin_mi2 is there any other way to solve this problem??
Srikavya1 can i know why you have used printf() in java?
nikeshprasad9 Printf is supported in java and it is done for formatting the output we print on the screen. Like you use System.out.println it moves the cursor on a new line after printing the statement System.out.print keeps the cursor at the same line after printing the statement Similarly System.out.printf is used to format the output like the one to be done in this question. You can also use System.out.format to format the output. Hope you understand what I want to explain. Do ask again if you didn't :)
pavand2312 can you explain why should we use only printf here?
harshjain9708 could explain me this Sop Statement System.out.printf("%-15s%03d%n", s1, x);
umarbasha007 import java.util.Scanner;
public class Solution {
public static void main(String[] args) { Scanner sc=new Scanner(System.in); System.out.println("================================"); for(int i=0;i<3;i++) { String s1=sc.next(); int x=sc.nextInt(); //u can use \n also instead of %n, both works System.out.printf("%-15s%03d\n",s1,x); } System.out.println("================================"); }}
mailmacho This code is not printing any spaces. Please check
Evea_Zerin I meant the white space. How do we know it will be in between the int and the string? And not anywhere else
mullapudieswar20 "%-15s%03d%n" '-' : Indicates to left justify indicator '15s' : Indicates string's minimum field width & 's' dentotes string. '%': Again we used '%' it shows declaring antoher column '03d' : Here '0' represents placing 0 before number if it needs
(eg: 001,090) , 3d used for denoting 3 for integer's field width and 'd' is used for printing integer value. '%n' : prints new line
abhijeetwarik02 How do you know this?? what do you refer for java/?
mullapudieswar20 i just google it .
I learned a lot from documentation . It gives a very good information .
[link is below description ] (https://docs.oracle.com/javase/tutorial/java/)
abhijeetwarik02 Thanx i m gonna have online test for epam recruitments thats why i asked..
mullapudieswar20 Stack over flow also a good resourse .
suryakumar_mahe1 y printf instead of println??
abhijeetwarik02 printf gives more flexibility than println for such problems...
starshinesafaa21 Thank you
harshita_sharma1 what one have to do if instead we have to align it to right?
rohitankam101 the code is ruuning perfectly fine and both the outputs are similar then too none of the testcases are executing. Why??
jimmy5 here's my code and a good refrence at the bottom
import java.util.Scanner; public class Solution { public static void main(String[] args) { Scanner sc=new Scanner(System.in); System.out.println("================================"); for(int i=0;i<3;i++) { String s1=sc.next(); int x=sc.nextInt(); if(s1.length() > 10){ s1 = s1.substring(0, 10); } System.out.printf("%-15s%03d%n", s1, x); } System.out.println("================================"); } }http://www.homeandlearn.co.uk/java/java_formatted_strings.html
Always_a_learner Hello, I looked at that link too, but I didn't understand why I had to code like:
System.out.printf("%-15s%03d%n", s1, x);
and I couldn't do
System.out.printf("%-15s %03d %n", s1, x);
(with spaces between %-15s and %03d...)
shervinee In this case one additional space is included in your format
ikmansi System.out.println(String.format("%-15s", s1) + String.format("%03d", x));
simrankaur3293 Can you please explain this?
I was using System.out.printf("%-15s %s %03d", s1, x);
ans2sqb import java.util.Scanner;
public class Solution {
public static void main(String[] args) { Scanner sc=new Scanner(System.in); System.out.println("================================"); for(int i=0;i<3;i++){ String s1=sc.next(); int x=sc.nextInt(); System.out.printf("%-15s%03d",s1,x); System.out.println(); } System.out.println("================================"); }}
parija420 why it is not sc.nextLine(); sc.next(); only
tushart023 because we have to read only single string i.e group of charater. not a ful line. So that we use sc.next(); :)
nikhilshrivastav This code works \m/
bhumika_sethi45 * System.out.printf("%-14s %03d %n", s1, x); * In this statement can we use any other character in place of zero to pad the outputs leading digits ???
nhkarthick yes,we can
AmitMaharana import java.util.Scanner; public class Solution { public static void main(String[] args) { Scanner sc=new Scanner(System.in); System.out.println("================================"); for(int i=0;i<3;i++) { String s1=sc.next(); int x=sc.nextInt(); for(int j=0;j<15;j++){ if(s1.length()<15){ s1=s1+" "; } } System.out.print(s1); System.out.println(String.format("%03d", x)); } System.out.println("================================"); } }
Plenoge Couple comments for this code. First and foremost, the problem was to test your knowledge of printf.
Otherwise looking just at your solution, instead of starting at j=0, you could start at s1.length() which would save you from the unnecessary loops where "if(s1.length() < 15)" is false. In fact, with the correcty initialized for loop, you could skip the if statement entirely.
Also, I wouldn't recommend building up your string in this way (printf aside) as the String is immutable and you're simply wasting memory. Java cannot optimize these appends as they occur on separate lines. You want StringBuilder here instead: http://stackoverflow.com/a/7817989/819373
surajnarayan System.out.println(String.format("%03d", x)); what will happen if i not write String .format and wat is its use here in this context??
abdtechgeek System.out.printf("%-15s%03d%n", s1, x);
This is the Correct code snippet according to me. %-15s : for left allined string with 15 offset %03d : for 3 digit num with leading zeros when length is lesser than 3 %n for new line
Refer : https://docs.oracle.com/javase/tutorial/java/data/numberformat.html
fixaaron Here's another printf ref:
https://www.cs.colostate.edu/~cs160/.Summer16/resources/Java_printf_method_quick_reference.pdf
anurag10101 public class Test { public static void main(String[]args) { Scanner sc=new Scanner(System.in); System.out.println("================================"); for(int i=0; i<3; i++) { String sl=sc.next(); int x = sc.nextInt(); System.out.printf("%-15s%03d%n", sl, x); } System.out.println("================================"); } }
As a begginer I dont expect other people to come up with a solution in less than 20 mins.
As a begginer it took me around 2 hours looking at countless youtube videos about this before finnaly getting to this- https://www.youtube.com/watch?v=moQ3Kr8ouiU
this dude has done a 12 part series all about printf statements in java! By far the there is out there! You can come here and copy/paste the code to congratulate yourself or you can look up all 12 videos of this guy and get FULL understanding of printf in JAVA!
Do yourself a favour and watch his videos! 'printf' is much larger than you realise!
I kept getting it wrong and 4 hours later I gave up and came to discussions only to realise my code is 99% right. One this that wasnt right was
%nwhich is bassically new line for printf, could have saved my 1 and a half hour by being more careful myself!
AaronT53 My solution which is correct still counts as the wrong , im not sure what the cause of this is but my output conforms to the rules perfectly. PFB my code. System.out.printf("%-15s %03d%n",s1,x);
yskchowdary4 Can any one give the code in the same formated output with System.out.println();??????????????????
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