can you please explain this line. thanks"("%-15s%03d%n", s1, x);"

well done

I am getting this error. error: no suitable method found for println(String,String,int)

Maybe I'm thinking wrong, but if the string is too long (i.e "0123456789ABCDEF" )

You get

================================
Test           001
0123456789ABCDEF055
Example        349
================================

System.out.printf("%-15s%03d%n", s1, x);

printf means 

system.out.print or println i know but printf i can't please explain

can u plz tell what is this called basically and where can i learn this

how to get an outout 111115 for input 5?? instead of paddin zero can we add any other no.s ?

ohhh i cccc

wow this code is really simple one, i did this but it went for so loong code :(

Thanks

may i know , knapa There should be a "code" , but when the code is not wearing , did not find the right

first time saw this type of formatte .. thanks

great explanation!!!

Thanks you soo much for this code.

Please find the below link for your quick concept reference https://www.youtube.com/watch?v=Dj0oVoFkY1I

you can also use format------ System.out.format("%-15s%03d%n", s1, x);

thank u so much

After a sc.nextInt(); Statement when again for loop runs the first statement is reading a string So is it not possible that it will read an empty string? As we have heard that after reading int we should clear buffer or use empty sc.nextLine(); command. Please make me clear about why we do not need to clear buffer here? Thanks! your effort is appreciated.

We are using 's' and 'd' for string and int data types respectively, if I'm not wrong. Similarly, what should we use if we want to format other data types such a double, float, char etc.

love this

See this link for explanation: http://www.homeandlearn.co.uk/java/java_formatted_strings.html

can u plz explain how this loop is working??????

I know String s1=sc.next(); was already written in the code, but can we use nextLine() instead of next() ?

nice solution. But I think it could be explained in a better way.

Nice explaination!!!

pls tell me the meaning of this statement ** System.out.printf("%-15s%03d%n", s1, x);**

Had to change %-15 to %-14, otherwise the Test Case won´t let me pass. Oddly enough it still looks like i have one space too much on the Output Field.

Awasam... (y) Learn a new thing.. :)

what is mean of printf
System.out.printf("%-15s%03d%n", s1, x);

yeah it helps

simply copied from the editorial @MalazAlamir

in the for loop we just run the loop where do those value get stored ? like in c we have array to store but here we dont have array so where do we store the 3 values?

why %03d works but %3d does not ? whats the difference ?

why u use printf instead of println

what if we need right indentation?

For this same code, i got this run time error:

Exception in thread "main" java.util.InputMismatchException at java.util.Scanner.throwFor(Scanner.java:909) at java.util.Scanner.next(Scanner.java:1530) at java.util.Scanner.nextInt(Scanner.java:2160) at java.util.Scanner.nextInt(Scanner.java:2119) at Solution.main(Solution.java:10)

it giving me an error . It says no suitable meth0d found for println(string,string,int)

why you use printf insted of println

Great explination! Why doesn't that work with println instead of of printf?

but in the java what's meaning of printf(""); ???

What if instead of adding zeroes, i wanted to add ones? Would the code then be %-15s%13d%n?

thank you

any other way to solve this? Please

Thank you dude, thats really good :D

How to get the indent to right? Or to the center?

i dint get y printf

Does the formatted o/p works only with printf? How about System.out.print?

I never knew there was a method for formatting output before. Good Explanation.

What does it mean for padding to be left-justified? My intuition (which is wrong) makes me think that adding blanks to the right of the word (until a length of 15) would be "right-justified".

this isn't working in mine only printing "==================" that's it.

is there any other way to solve this problem??

can i know why you have used printf() in java?

can you explain why should we use only printf here?

could explain me this Sop Statement System.out.printf("%-15s%03d%n", s1, x);

import java.util.Scanner;

public class Solution {

public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        System.out.println("================================");
        for(int i=0;i<3;i++)
        {
            String s1=sc.next();
            int x=sc.nextInt();
            //u can use \n also instead of %n, both works
            System.out.printf("%-15s%03d\n",s1,x);
        }
        System.out.println("================================");

}

}

This code is not printing any spaces. Please check

"%-15s%03d%n" '-' : Indicates to left justify indicator '15s' : Indicates string's minimum field width & 's' dentotes string. '%': Again we used '%' it shows declaring antoher column '03d' : Here '0' represents placing 0 before number if it needs
(eg: 001,090) , 3d used for denoting 3 for integer's field width and 'd' is used for printing integer value. '%n' : prints new line

How do you know this?? what do you refer for java/?

y printf instead of println??

Hello, I looked at that link too, but I didn't understand why I had to code like:

System.out.printf("%-15s%03d%n", s1, x);

and I couldn't do

System.out.printf("%-15s %03d %n", s1, x);

(with spaces between %-15s and %03d...)

Can you please explain this?

I was using System.out.printf("%-15s %s %03d", s1, x);

Couple comments for this code. First and foremost, the problem was to test your knowledge of printf.

Otherwise looking just at your solution, instead of starting at j=0, you could start at s1.length() which would save you from the unnecessary loops where "if(s1.length() < 15)" is false. In fact, with the correcty initialized for loop, you could skip the if statement entirely.

Also, I wouldn't recommend building up your string in this way (printf aside) as the String is immutable and you're simply wasting memory. Java cannot optimize these appends as they occur on separate lines. You want StringBuilder here instead: http://stackoverflow.com/a/7817989/819373

System.out.println(String.format("%03d", x)); what will happen if i not write String .format and wat is its use here in this context??

why it is not sc.nextLine(); sc.next(); only

This code works \m/

yes,we can

Here's another printf ref:

https://www.cs.colostate.edu/~cs160/.Summer16/resources/Java_printf_method_quick_reference.pdf

the test cases are broken, the left-justification is actually -14 chars not -15, try it it'll work EDIT: just tried with opening the problem page again, now it works with -15 left-justification...weird.