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publicstaticintB=1;publicstaticintH=1;publicstaticbooleanflag=true;static{Scannerscan=newScanner(System.in);B=scan.nextInt();H=scan.nextInt();scan.close();if(B<=0||H<=0){flag=false;System.out.println("java.lang.Exception: Breadth and height must be positive");}}
Test 6 is testing for the upper bound of < 100. If you look in the constraints you will see that the number entered must be greater than -100 and less than 100. The test is failing because it tests a height of 100. The crazy thing that is missing is they do not tell you what should display when this situation happens. But what it is expecting is the exception that you get when your height or breadth is negative.
Java Static Initializer Block
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can you show me the way without exception?tks
Like this:
Your answer is fail to pass the 6th test case.!!
Sorry. It should be "if (B <= 0 || H <= 0)". You can try again.
It is the same thing. And Answer comes by this.
Test 6 is testing for the upper bound of < 100. If you look in the constraints you will see that the number entered must be greater than -100 and less than 100. The test is failing because it tests a height of 100. The crazy thing that is missing is they do not tell you what should display when this situation happens. But what it is expecting is the exception that you get when your height or breadth is negative.
@catequil Thanks, you are right. But the constrains are actually: -100 <= B <= 100 -100 <= H <= 100
So the 100 should be included. I guess it's a mistake that Testcase 6 fails, when you take the input 100 for valid.
No need to initialize variables B, H and flag.
I think we have to initialize flag...
thanks for the solution...also..no need to intialise....
what is the use of flag over here??
public static int B = 1; public static int H = 1; public static boolean flag = true; static{ }
"can u explain me plzz why have used this?????"