We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
Instead of using or you can use multiplication i.e, if bh<0 the string is printed. This is better because, if we extend the code this format will be better to debug.
I found twice repeating "java.lang.Exception:" in your code.
Line 17 should be corrected as :
throw new Exception("Breadth and height must be positive");
static int B,H;
static boolean flag = true;
static Scanner scan = new Scanner(System.in);
static{
B = scan.nextInt();
scan.nextLine();
H = scan.nextInt();
scan.close();
if(B<= 0 || H<=0){
flag = false;
System.out.println("java.lang.Exception: Breadth and height must be positive");
}
Java Static Initializer Block
You are viewing a single comment's thread. Return to all comments →
Instead of using or you can use multiplication i.e, if bh<0 the string is printed. This is better because, if we extend the code this format will be better to debug.
we should not use bh<0 condition because if b and h both are negative, then your code will set flag as true which is incorrect
we cant use this as if both b & h are negative the condition will get true which should not be happen
if both b & h are negative the condition will get false and it throw the exception
why do we need flag in this to true can we use and operator insted of or .................................please help
I found twice repeating "java.lang.Exception:" in your code. Line 17 should be corrected as : throw new Exception("Breadth and height must be positive");
static int B,H; static boolean flag = true; static Scanner scan = new Scanner(System.in); static{ B = scan.nextInt(); scan.nextLine(); H = scan.nextInt(); scan.close();
}
This works fine.