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@above No that code is too complicated. The else if statement is not neccessary (just need an else statement). You just need to set flag = true when both are greater than 0. (Lengths can't be negative)
your program is correct but how i am not able to understand the logic behind this
if ((B<0 && H<0)&&(B>=0&&H>=0))
suppose :we will give input 1and 3 then it shoud go to false block
because
B<0 && H<0 =false
B>=0&& H>=0=True
false && true
false should come
This one is the correct code you have written if block wrong.
static int B,H;
static boolean flag=true;
static{
Scanner scan = new Scanner(System.in);
B = scan.nextInt();
scan.nextLine();
H = scan.nextInt();
scan.close();
if(B>0 && H>0){
flag = true;
}else if((B<0 && H<0)||(B<=0 && H>=0)||(B>=0 && H<=0)){
flag=false;
System.out.println("java.lang.Exception: Breadth and height must be positive");
}
}
It won't give the correct answer. you need to remove the less than condition from the first if. other than that there is no need of second if else only else is needed.
It was not passing two test cases so i did some modification
static boolean flag = true; static int B,H;
static{
Scanner scan = new Scanner(System.in);
B = scan.nextInt();
scan.nextLine();
H = scan.nextInt();
scan.close();
if(B>0 && H>0){
flag = true;
}else{
flag=false;
System.out.println("java.lang.Exception: Breadth and height must be positive");
}
}
static boolean flag = true;
static int B,H;
static{
Scanner scan = new Scanner(System.in);
B = scan.nextInt();
H = scan.nextInt();
scan.close();
if(B<=0||H<=0){
flag=false;
System.out.println("java.lang.Exception: Breadth and height must be positive");
}else
flag=true;
}
#this is the actual output
your output fails in two of the given test cases
This code works better, it clears all test cases
static boolean flag = true;
static int B,H;
static
{
Scanner scan = new Scanner(System.in);
B = scan.nextInt();
H = scan.nextInt();
if((B>0 && H>0))
{
flag = true;
}
else
{
flag=false;
System.out.println("java.lang.Exception: Breadth and height must be positive");
}
}
Here i've just declared B,H as static variables because static methods involve use of static variables. flag is just initialized to default boolean value which can either be set as true or false doesn't make a difference.
Scanner sc = new Scanner(System.in);
B = sc.nextInt();
sc.nextLine();
H = sc.nextInt();
if(B>0 && H>0){
flag = true;
}else{
flag = false;
System.out.println("java.lang.Exception: Breadth and height must be positive");
}
}
Java Static Initializer Block
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static boolean flag = true; static int B,H;
static{
}
@above No that code is too complicated. The else if statement is not neccessary (just need an else statement). You just need to set flag = true when both are greater than 0. (Lengths can't be negative)
https://stackoverflow.com/questions/2070293/why-doesnt-java-allow-to-throw-a-checked-exception-from-static-initialization-b
You have a error in else if() block
Here is the actual answer
static boolean flag = true; static int B,H; static { Scanner scan = new Scanner(System.in); B = scan.nextInt(); scan.nextLine(); H = scan.nextInt(); scan.close(); if((B<0 && H<0)&&(B>=0 && H>=0)) { flag = true; } else if((B<=0 && H<=0)||(B>=0 && H<=0)||(B<=0 && H>=0)) { flag=false; System.out.println("java.lang.Exception: Breadth and height must be positive"); } }
your program is correct but how i am not able to understand the logic behind this if ((B<0 && H<0)&&(B>=0&&H>=0)) suppose :we will give input 1and 3 then it shoud go to false block because B<0 && H<0 =false B>=0&& H>=0=True false && true false should come
why so many comparison operator dude. Simply below would work just fine.
static boolean flag = true; static int B, H; static Scanner sc = new Scanner(System.in);
static { B = sc.nextInt(); H = sc.nextInt();
What if B and H are Both 0?
Better be B<0 || H<0.
If both are 0, there should be an Exception, it's written in the task:
it doesn't works fine. it gives some expression error bcoj u use static keyword before Scanner class.....
This works
static int B,H; static boolean flag=true; static Scanner sc=new Scanner(System.in); static{ B=sc.nextInt(); sc.nextLine(); H=sc.nextInt(); sc.close(); if((B>=0&&H>=0)&&(B!=0&&B!=100)&&(H!=0&&H!=100)){ flag=true; }else{ flag=false; System.out.println("java.lang.Exception: Breadth and height must be positive"); }
why did we keep the whole loop in a static block
it doesn't matter
if not, it is throwing an error
what is the use of nextLine() bro
This one is the correct code you have written if block wrong. static int B,H; static boolean flag=true; static{ Scanner scan = new Scanner(System.in); B = scan.nextInt(); scan.nextLine(); H = scan.nextInt(); scan.close(); if(B>0 && H>0){ flag = true;
}else if((B<0 && H<0)||(B<=0 && H>=0)||(B>=0 && H<=0)){ flag=false; System.out.println("java.lang.Exception: Breadth and height must be positive"); } }
It won't give the correct answer. you need to remove the less than condition from the first if. other than that there is no need of second if else only else is needed.
can you explain how you directly used B,H as variables instead specifying any datatypes for that.
He used int .Read carefully you can find it.
It was not passing two test cases so i did some modification
static boolean flag = true; static int B,H; static{ Scanner scan = new Scanner(System.in); B = scan.nextInt(); scan.nextLine(); H = scan.nextInt(); scan.close(); if(B>0 && H>0){ flag = true;
}else{ flag=false; System.out.println("java.lang.Exception: Breadth and height must be positive"); } }
thanks..this is giving correct answer. I was missing to update the flag as false in else loop.
static boolean flag = true; static int B,H;
static{
Scanner scan = new Scanner(System.in); B = scan.nextInt(); scan.nextLine(); H = scan.nextInt(); scan.close(); if(B>0 && H>0){ flag = true;
}else{ flag=false; System.out.println("java.lang.Exception: Breadth and height must be positive"); } }
static boolean flag = true; static int B,H;
static{ Scanner s=new Scanner(System.in); B=s.nextInt(); s.nextLine(); H=s.nextInt(); s.close(); if(H<=0 || B<=0){ flag=false; System.out.println("java.lang.Exception: Breadth and height must be positive"); } }
static boolean flag = true; static int B,H; static{ Scanner scan = new Scanner(System.in); B = scan.nextInt(); H = scan.nextInt(); scan.close(); if(B<=0||H<=0){ flag=false; System.out.println("java.lang.Exception: Breadth and height must be positive"); }else flag=true; }
why we should keep in static block?
yr god has got some errors here is the errorless code
/............................................./ static boolean flag = true; static int B,H;
static {
Scanner scan = new Scanner(System.in); B = scan.nextInt(); scan.nextLine(); H = scan.nextInt(); scan.close(); if(B>0 && H>0) { flag = true;
} else if((B<=0 && H>=0)||(B>=0 && H<=0)||(B<=0 && H<=0)) { flag=false; System.out.println("java.lang.Exception: Breadth and height must be positive"); } }
Your If and else if conditions are wrong. keep it simple silly.
if(B>0 && H>0){ flag = true;
}else { flag=false; System.out.println("java.lang.Exception: Breadth and height must be positive"); }
your solution satisfies only problem's requirements but my solution covers all possibilities.
This code works better, it clears all test cases static boolean flag = true; static int B,H;
static { Scanner scan = new Scanner(System.in); B = scan.nextInt(); H = scan.nextInt(); if((B>0 && H>0)) { flag = true; } else { flag=false; System.out.println("java.lang.Exception: Breadth and height must be positive"); } }
Why we use static block here
This is because we have been told to use static block in this problem.
thanks bro
static boolean flag = true; static int B,H; please explain this.....
Here i've just declared B,H as static variables because static methods involve use of static variables. flag is just initialized to default boolean value which can either be set as true or false doesn't make a difference.
this is not satisfying few test cases even
It should, it worked fine for me which is why i posted my code.
ok!!thanku
Your code gives wrong answer in some test case insted do this :-
if(B>0 && H>0){ flag = true;
}else{ flag=false; System.out.println("java.lang.Exception: Breadth and height must be positive"); }
yes!!there r few cases which r not satisfying...but mild changes can be done the some code
// Much simpler one.
Scanner sc = new Scanner(System.in); B = sc.nextInt(); sc.nextLine(); H = sc.nextInt(); if(B>0 && H>0){ flag = true; }else{ flag = false; System.out.println("java.lang.Exception: Breadth and height must be positive"); } }
In this testcas 3 and 6 become failed.
What's the reason for usage of scan.nextLine() here? will you please explain !