Java Stdin and Stdout I
byShafaet
TopazJ Scanner sc=new Scanner(System.in); while(sc.hasNextInt()){ int a=sc.nextInt(); System.out.println(a); }is cleaner, especially if the test cases don't input 3 integers only...
gajapathiraju501 This will also works fine, if we restrict loop for 3 inputs. for(int i=0;i<3;i++){ int a=sc.nextInt();
System.out.println(a); }
Mr_Swiergiwits My solution was nearly identical to yours however in your solution you force the program to instantiate "a" every time the loop is iterated. This can cause unneeded computation.
mongaretcm System.out.println(a); Then loop over -System.out.println(sc.next()); checking while scanner has next int That worked out just fine
shyam_bipul nice there are more use of this functions to imput max no of value at rum time
chandrashekarga1 maam,could you please explain me how does implementing while loop got worked out in detail
sunvictor The while loop runs if there is another input otherwise it just doesn't run
hasNextInt() checks if the next input is an int so the while loop just checks if there is a next int
kamal10_rk hasNextInt checks for input,then while loop evaluates the hasNextInt if true while is executed.
chandrashekarga1 maam,could you please explain me how does implementing while loop got worked out in detail and also if could explain about how those test cases failed ? what is the reason?
ankit15120 Hi TopazJ! How can i make this Scanner wait for, let say 3 seconds and If no more input till 3 seconds ,the loop ends.
correajunk Just use System.out.println(sc.nextInt());
ketechimelorudo You can make it more simpler by just typing this.
Scanner scan = new Scanner(System.in); while(scan.hasNext()) System.out.println(scan.next());
You are just printing a value not passing it to 'a'
eross8713 // even cleaner Scanner scan = new Scanner(System.in); while(scan.hasNextInt()){ System.out.println(scan.nextInt()); }ketechimelorudo // Even better
public class Solution {
public static void main(String[] args) { Scanner scan = new Scanner(System.in); scan.forEachRemaining(System.out::println); }}
hallyyy i'm just new.. and also like to learn the other coding styles from the others. But just a quick question though.. when i tried your code for Java 8, it worked. However, when i tried it for Java 7.. it gives me error.
this is the Java 7
this is the Java 8
gaurav_1998 i would like to do it by defining an array and giving it's value.Could u please give me code for that.
Sravya_07 import java.util.*;
public class Solution {
public static void main(String[] args) { Scanner scan = new Scanner(System.in); int[] a= new int[3]; //creating array for (int i=0;i<3;i++) //Assigning values to array from stdin a[i] = scan.nextInt(); scan.close(); for(int j=0;j<3;j++) //Printing array values to stdout System.out.println(a[j]); }}
rishikeshwar419 how?
Tanjib123 import java.util.*; public class Solution { public static void main(String[] args) { Scanner scan = new Scanner(System.in); int a = scan.nextInt(); int b = scan.nextInt(); int c = scan.nextInt(); System.out.println(a+"\n"+b+"\n"+c); } } // This is shorter code!
tanweiyon What is meant by 'new'?
umarbasha007 import java.util.*;
public class Solution {
public static void main(String[] args) { Scanner scan = new Scanner(System.in); int a = scan.nextInt(); int b = scan.nextInt(); intt c = scan.nextInt(); //Print int values in single line code System.out.printf("%d\n%d\n%d\n",a,b,c); }}
sinha_amrit093 Heres mine. Hope it helps!
import java.util.*; public class Solution { public static void main(String[] args) { Scanner scan = new Scanner(System.in); for(int i=0;i<3;i++) { int a=scan.nextInt(); System.out.println(a); } scan.close(); } }
zibibednarek Had the same Idea, than I tohught about using arrays, as it would be easier to modify number of integers we would like to input and than printout to console.
System.out.println("Input integers"); Scanner readIntegers = new Scanner(System.in); int[] Integers; Integers = new int[3]; for(int i=0; i<3 ; i++){ Integers [i] = readIntegers.nextInt(); } readIntegers.close(); //It's not necessary, as the input Loop is set to run 3 times only System.out.println("Output integers"); for(int i=0 ; i<3 ; i ++){ System.out.println(Integers[i]); }sinha_amrit093 Yeah pretty much the same thing. The only difference is that yours requires a longer compilation time. :)
aurelius0523 try (Scanner scan = new Scanner(System.in)) { while (scan.hasNext()) { System.out.println(scan.nextInt()); } }
You can do a Try with Resource to automatically close any classes that implements
AutoClosableinterface (Scanner class in this case). That way you don't have to doscanner.close
sohamghorpade18 why do we include * in packages??
ex. java.io.*;
igoorderke "*" symbol adds all the classes from the package. instead of typing out all the classes in java.io package we can add a star, which is not very efficient if you write a small program, sometimes it is better to add single class. EX: java.io.FileReader java.io.FileWriter
ajaykumar_bit_11 try this out.
import java.util.*;
public class Solution {
public static void main(String[] args) { Scanner scan = new Scanner(System.in); int i; int a = scan.nextInt(); int b = scan.nextInt(); int c = scan.nextInt(); System.out.println(a); System.out.println(b); System.out.println(c); }}
coderboy_ [deleted]
naveen_km24 Scanner scan = new Scanner(System.in); while(scan.hasNextInt()){ System.out.println(scan.next()); } scan.close(); // Remember to close the scanner after you are done using it.
ikmansi No need to store in variable as we are not processing them.
Scanner sc = new Scanner(System.in); for(int i=0; i<3; i++){ System.out.println(sc.nextInt()); }sciencenerd1609 yes but in this code it will ask for input and print it in the next line and then ask for 2nd value ..the objective is to input 3 values and print them in separate lines together ..
Sravya_07 import java.util.; import java.io.;
public class Solution1 {
public static void main(String[] args) throws IOException{ InputStreamReader r = new InputStreamReader(System.in); BufferedReader br =new BufferedReader(r); String[] value=new String[3]; int i=0; while(i<3){ value[i]=br.readLine(); i++; } br.close(); r.close(); for(int j=0;j<3;j++) System.out.println(value[j]); }}
lizu036 if you know the number of inputs then you can use loops like
import java.util.*;
public class Solution {
public static void main(String[] args) { Scanner scan = new Scanner(System.in); for(int a=1;a<=3;a++){ int b = scan.nextInt(); System.out.println(b); } }}
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