This will also works fine, if we restrict loop for 3 inputs. for(int i=0;i<3;i++){ int a=sc.nextInt();
System.out.println(a); }

My solution was nearly identical to yours however in your solution you force the program to instantiate "a" every time the loop is iterated. This can cause unneeded computation.

nice there are more use of this functions to imput max no of value at rum time

maam,could you please explain me how does implementing while loop got worked out in detail

maam,could you please explain me how does implementing while loop got worked out in detail and also if could explain about how those test cases failed ? what is the reason?

Hi TopazJ! How can i make this Scanner wait for, let say 3 seconds and If no more input till 3 seconds ,the loop ends.

Just use System.out.println(sc.nextInt());

You can make it more simpler by just typing this.

Scanner scan = new Scanner(System.in); while(scan.hasNext()) System.out.println(scan.next());

You are just printing a value not passing it to 'a'

    // even cleaner
    Scanner scan = new Scanner(System.in);        
    while(scan.hasNextInt()){
        System.out.println(scan.nextInt());
    }

i would like to do it by defining an array and giving it's value.Could u please give me code for that.

how?

tnq.

import java.util.*;

public class Solution {

public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);
    int a = scan.nextInt();
    int b = scan.nextInt();
    int c =scan.nextInt();

    System.out.println(a);
   System.out.println(b);
   System.out.println(c);
}

}

It is just showing me the compiler error!

Seems like the shortest solution is the following:

        Scanner sc=new Scanner(System.in);
        while(sc.hasNextInt()){
            System.out.println(sc.nextInt());
        }

following after @TopazJ. My original grep about it was how would it close because the original challenge didn't ask for this or say something about how to close it with something other than an 'int'. But I guess this is a creative solution.

What is meant by 'new'?

import java.util.*;

public class Solution {

public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);
    int a = scan.nextInt();
    int b = scan.nextInt();
    intt c = scan.nextInt();

            //Print int values in single line code
    System.out.printf("%d\n%d\n%d\n",a,b,c);

}

}

Had the same Idea, than I tohught about using arrays, as it would be easier to modify number of integers we would like to input and than printout to console.

    System.out.println("Input integers");

    Scanner readIntegers = new Scanner(System.in);

    int[] Integers;
    Integers = new int[3];

    for(int i=0; i<3 ; i++){
        Integers [i] = readIntegers.nextInt();
    }
        readIntegers.close(); //It's not necessary, as the input Loop is set to run  3 times only

    System.out.println("Output integers");
    for(int i=0 ; i<3 ; i ++){
        System.out.println(Integers[i]);
    }

"*" symbol adds all the classes from the package. instead of typing out all the classes in java.io package we can add a star, which is not very efficient if you write a small program, sometimes it is better to add single class. EX: java.io.FileReader java.io.FileWriter

yes but in this code it will ask for input and print it in the next line and then ask for 2nd value ..the objective is to input 3 values and print them in separate lines together ..