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  1. Prepare
  2. Java
  3. Introduction
  4. Java Stdin and Stdout II
  5. Discussions

Java Stdin and Stdout II

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1232 Discussions

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  • yogapriyan_m
     + 2 comments

    For those who curious to know why sc.nextLine( ) used two times

    YT - https://youtu.be/_xqzmDyLWvs

    use this

  • kaveri62002
     + 1 comment

    We use the nextLine() in the String then only we get the output, It reads the text which was written by us. Code:- import java.util.Scanner;

    public class Solution {

    public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);
    int i = scan.nextInt();
    double d=scan.nextDouble();
    scan.nextLine();
    String s=scan.nextLine();

    // Write your code here.

    System.out.println("String: " + s);
    System.out.println("Double: " + d);
    System.out.println("Int: " + i);
}

    }

  • gamerhmv2050
     + 1 comment

    wtf is this bullshit

  • Pranavkadam0967
     + 1 comment

    import java.util.Scanner;

    class Solution { public static void main(String args[]) { Scanner sc = new Scanner(System.in);

        int n = sc.nextInt();
    double d = sc.nextDouble();
    sc.nextLine();
    String s = sc.nextLine();

    sc.close();

    System.out.println("String: " + s);
    System.out.println("Double: " + d);
    System.out.println("Int: " + n);
}

    }

  • SVVBathini_w
     + 1 comment

    For Java15 Platform

    I wrote the code from scratch just to get more practice

    import java.util.Scanner;

class Solution
{
    public static void main(String args[])
    {
        Scanner sc = new Scanner(System.in);
        
        int n = sc.nextInt();
        double d = sc.nextDouble();
        sc.nextLine();
        String s = sc.nextLine();
        
        sc.close();
        
        System.out.println("String: " + s);
        System.out.println("Double: " + d);
        System.out.println("Int: " + n);
    }
}