We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
Java Stdin and Stdout II
Java Stdin and Stdout II
Sort by
recency
|
1220 Discussions
|
Please Login in order to post a comment
How this test case getting passed. Im confused can someone explain this.
Compiler Message Success
Input (stdin)
2147483647 235345345345.234534 fsdfsdf sdf
Expected Output
String: fsdfsdf sdf Double: 2.3534534534523453E11 Int: 2147483647
This was my original solution:
I'm not really sure why this doesnt satisfy the test cases, although it prints as expected
Unlike the scanner.nextLine() method, the scanner.nextInt() method only consumes the integer part and leaves the enter or newline character in the input buffer.
When the third scanner.nextLine() is called, it finds the enter or newline character still existing in the input buffer, mistakes it as the input from the user, and returns immediately.
There are two ways to solve this problem. You can either consume the newline character after the scanner.nextInt() call takes place, or you can take all the inputs as strings and parse them to the correct data type later on.
Java is such a versatile and powerful language—it's amazing how it's still going strong after all these years. betguru247.net