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  1. Prepare
  2. Java
  3. Strings
  4. Java Strings Introduction
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Java Strings Introduction

  • abramowicz
     + 0 comments

    Strings in Java are immutable, so every invocation of .substring(), .replace() , .toUpperCase() or concatenation with + creates a new String object. Thus, I prefer converting a String to character array or use StringBuilder class that encapsulates a mutable buffer and provides a set of methods to operate on it in a meaningful name. In the end, it creates a new String, of course, but it scales well with the number of applied operations.

    My solution looks as follows:

    import java.util.Scanner;

public class Solution {
    private static String capitalizeFirst(String str) {
        StringBuilder sb = new StringBuilder(str);
        sb.setCharAt(0, Character.toUpperCase(str.charAt(0)));
        return sb.toString();
    }
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        String a = sc.nextLine();
        String b = sc.nextLine();
        sc.close();
        System.out.println(a.length() + b.length());
        System.out.println((a.compareTo(b) > 0) ? "Yes" : "No");
        System.out.println(capitalizeFirst(a) + " " + capitalizeFirst(b));
    }
}