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let sorting = nums.sort((a, b) => a - b);
let largest = sorting[0];
let secLargest = sorting[0]
for(let i=0;ilargest)
{
secLargest = largest;
largest = sorting[i]
}
}
return(secLargest)
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Day 3: Arrays
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i guess its the simple method
let sorting = nums.sort((a, b) => a - b); let largest = sorting[0]; let secLargest = sorting[0] for(let i=0;ilargest) { secLargest = largest; largest = sorting[i] } } return(secLargest)