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  1. Prepare
  2. Tutorials
  3. 10 Days of Javascript
  4. Day 3: Arrays
  5. Discussions

Day 3: Arrays

  • amanhaidry
     + 0 comments

    Simple solution in single loop

    function getSecondLargest(nums) {
    // Complete the function
    let largest = nums[0];
    let secondLargest= nums[0];
    let n= nums.length ;
    
    for(let i=0; i<n; i++){
        if(nums[i]>largest){
            secondLargest=largest;
            largest= nums[i];
        }else if(nums[i]>secondLargest && nums[i]!= largest){
            secondLargest= nums[i];
        }
    }
    return secondLargest;
}