We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Tutorials
  3. 10 Days of Javascript
  4. Day 5: Arrow Functions
  5. Discussions

Day 5: Arrow Functions

Sort by

recency

|

443 Discussions

|

  • myclg7
     + 0 comments
    function modifyArray(nums) {
    const arr = nums.map((e)=>{
       if(e%2==0){
        return e*2;
       } else{
        return e*3;
       }
    });
    return arr;
}

  • Bye_Shuvo
     + 0 comments
    const modifyArray = (nums) => {
    return nums.map((num)=>{return (num%2 === 0)?(num*2):(num*3)})
}

    this is the simpliest way to do it , where map() creates a new array from calling a function for every array element and does not change the original array. then just return the new array for modifyArray function.

  • jonlle19
     + 0 comments
    function modifyArray(nums) {
    return nums.map(num => num % 2 === 0 ? num * 2 : num * 3)
}

  • alerpiniere
     + 0 comments
    function modifyArray(nums) {
    return nums.map(n => {
        return n * (2 + n%2)
    })
}

  • uisamratc
     + 0 comments

    In JS

    function modifyArray(nums) {
    const res = nums.map((val) => {
  if (val % 2 == 0) {
    return val * 2;
  } else {
    return val * 3;
  }
});

return res;

}