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  1. Prepare
  2. Tutorials
  3. 10 Days of Javascript
  4. Day 5: Arrow Functions
  5. Discussions

Day 5: Arrow Functions

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444 Discussions

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  • camila_lm
     + 0 comments
    function modifyArray(nums) {
  const transform = x => x % 2 == 0 ? x * 2 : x * 3;
  return nums.map(transform);
}

  • myclg7
     + 0 comments
    function modifyArray(nums) {
    const arr = nums.map((e)=>{
       if(e%2==0){
        return e*2;
       } else{
        return e*3;
       }
    });
    return arr;
}

  • Bye_Shuvo
     + 0 comments
    const modifyArray = (nums) => {
    return nums.map((num)=>{return (num%2 === 0)?(num*2):(num*3)})
}

    this is the simpliest way to do it , where map() creates a new array from calling a function for every array element and does not change the original array. then just return the new array for modifyArray function.

  • jonlle19
     + 0 comments
    function modifyArray(nums) {
    return nums.map(num => num % 2 === 0 ? num * 2 : num * 3)
}

  • alerpiniere
     + 0 comments
    function modifyArray(nums) {
    return nums.map(n => {
        return n * (2 + n%2)
    })
}