function vowelsAndConsonants(s) { const vowels = ['a', 'e', 'i', 'o', 'u']; let consonants = []; for (let char of s) { if (vowels.includes(char)) { console.log(char); } else { consonants.push(char);
} }

for(let char of consonants)
{
    console.log(char);
}

}

function vowelsAndConsonants(s) { const vowels = "aeiou";

// First loop: print vowels
for (let ch of s) {
    if (vowels.includes(ch)) {
        console.log(ch);
    }
}

// Second loop: print consonants
for (let ch of s) {
    if (!vowels.includes(ch)) {
        console.log(ch);
    }
}

}

This was my solution. I turned it into an array and then used a forEach which probably wasn't the best for what I was doing as I've still not figured out when it's better to use a for vs forEach,

function vowelsAndConsonants(s) {
    const stringArray = s.split("");
    
    stringArray.forEach((letter)=>{        
        if(/[aeiou]/.test(letter)){
            console.log(letter)
        }
    })
    stringArray.forEach((letter)=>{        
        if(!/[aeiou]/.test(letter)){
            console.log(letter)
        }
    }
    )
}

function vowelsAndConsonants(s) { var consonantsChars=[] var myArr= s.split(''); var vowelChars= myArr.filter(function(char){ if(char=='a' ||char=='e'||char=='i'||char=='o'||char=='u'){ return 1; }else{ consonantsChars.push(char) ; } } ) vowelChars.forEach(char=>{ console.log(char); }) consonantsChars.forEach(char=>{ console.log(char); }) }