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  1. Prepare
  2. Tutorials
  3. 10 Days of Javascript
  4. Day 7: Regular Expressions I
  5. Discussions

Day 7: Regular Expressions I

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  • townsendTangler
     + 0 comments

    After reading others posts, there seem to be much better ways to do this than what I hacked together.

    see...

        var re = /^[a].+[a]$|^[e].+[e]$|^[i].+[i]$|^[o].+$[o]|^[u].+$[u]/;
    
    /*
     * Do not remove the return statement
     */
    
    return re;

  • mayanksaraswat42
     + 2 comments
    function regexVar() {
   
    let re = /^([aeiou]).+\1$/;
 
    return re;
}

  • lieselu22
     + 1 comment
    function regexVar(s) {
   
    let re = /^([aeiou]).*\1$/i

    return re;
}

  • valleriasouza28
     + 0 comments

    Hello everyone, I wrote this code:

    const str = "abcdo"
let strCase
let RegExp = /a|e|i|o|u/
let firstLetterTest
let lastLetterTest
let firstLetter
let lastLetter

strCase = str.toLowerCase()
firstLetter = strCase[0]
lastLetter = strCase[-1]
    
firstLetterTest = RegExp.test(firstLetter)
lastLetterTest = RegExp.test(lastLetter)

if(firstLetterTest === false ||lastLetterTest === false) {
  return console.log(false)
} else {
let re = strCase.startsWith(firstLetter) && strCase.endsWith(firstLetter)
}

    as a solution to the problem, of course I tried to adapt it by passing str as a parameter to the function and changing the name of the function's return variable. Thanks if anyone has solutions for improvements...

  • tranvn98
     + 0 comments

    function regexVar() { /* * Declare a RegExp object variable named 're' * It must match a string that starts and ends with the same vowel (i.e., {a, e, i, o, u}) */

      let re = /^([aeiou]).*\1$/;
/*
 * Do not remove the return statement
 */
return re;

    }

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