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  1. Prepare
  2. Tutorials
  3. 10 Days of Javascript
  4. Day 2: Conditional Statements: Switch
  5. Discussions

Day 2: Conditional Statements: Switch

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369 Discussions

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  • jagadishjajimog1
     + 0 comments

    //My Solution

    function getLetter(s){ let letter;

                    switch(s[0]){
                        case 'a' : 
                        case 'e' :
                        case 'i' : 
                        case 'o' :
                        case 'u' :
                                    letter = 'A';
                                    break;
                        case 'b' :
                        case 'c' :
                        case 'd' :
                        case 'f' :
                        case 'g' :
                                    letter = 'B';
                                    break;
                        case 'h' :
                        case 'j' :
                        case 'k' :
                        case 'l' :
                        case 'm' :
                                    letter = 'C';
                                    break;
                        default:
                                    letter = 'D';
                                    break;
            }
            return letter;
}

  • slavynskyi_denys
     + 0 comments
    function getLetter(s) {
    switch(true) {
        case 'aeiou'.includes(s[0]): return 'A';
        case 'bcdfg'.includes(s[0]): return 'B';
        case 'hjklm'.includes(s[0]): return 'C';
        default: return 'D'
    }
}

  • edgar_zh_osorio
     + 0 comments

    My solution

    function getLetter(s) {
    let letter;
    // Write your code here
    const data = {
        A: ['a', 'e', 'i', 'o', 'u'],
        B: ['b', 'c', 'd', 'f', 'g'],
        C: ['h', 'j', 'k', 'l', 'm'],
        D: ['n', 'p', 'q', 'r', 's', 't', 'v', 'w', 'x', 'y', 'z']
    }
    
    switch(s[0]) {
        case data.A.find( item => (item === s[0])):
            letter = 'A';
        break;  
        case data.B.find( item => (item === s[0])):
            letter = 'B';
        break; 
        case data.C.find( item => (item === s[0])):
            letter = 'C';
        break;  
        case data.D.find( item => (item === s[0])):
            letter = 'D';
        break; 
    }
    return letter;
}

  • sazidthe1
     + 0 comments

    Here's my solution:

    function getLetter(s) {
    let firstChar = s.charAt(0);
    let letter;
    switch (true) {
        case new Set(['a','e','i','o','u']).has(firstChar):
            letter = "A";
            break;
        case new Set(['b','c','d','f','g']).has(firstChar):
            letter = "B";
            break;
        case new Set(['h','j','k','l','m']).has(firstChar):
            letter = "C";
            break;
        default:
            letter = "D";
   }
   return letter;
}

  • julianbacab_dc7
     + 0 comments

    This is my solution

    function getLetter(s) {
    let letter = s;
    
    
    // Write your code here
    switch(true) {
        case ["a","e","i","o","u"].includes(letter[0]) :
                letter = "A";
                break;
        case ["b","c","d","f","g"].includes(letter[0]):
                letter = "B";
                break;
        case ["h","j","k","l","m"].includes(letter[0]):
                letter = "C";
                break;
        case ["n","p","q","r","s", "t", "v", "w","x","y","z"].includes(letter[0]):
                letter = "D";
                break;
    }
    
    return letter;
}