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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Jumping on the Clouds: Revisited
  5. Discussions

Jumping on the Clouds: Revisited

  • raveen_re
     + 0 comments

    Solution in JS

    function jumpingOnClouds(c, k) {
    let n = c.length;
    
    let i = k >= n ? Math.abs(n - k) : k;
    let e = 100 - (c[i] === 0 ? 1 : 3);
    
    while(i != 0 || e <= 0){
        i = i + k;
        if(i >= n){
            i = Math.abs(n - i);
        }
        
        if(c[i] === 0){
            e--;
        }
        
        else{
           e = e - 3;
        }
    }
    
    return e >= 0 ? e : 0;
}