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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Jumping on the Clouds: Revisited
  5. Discussions

Jumping on the Clouds: Revisited

  • gandymovspc
     + 1 comment

    Solution in JavaScript

    function jumpingOnClouds(c, k) {
	let energy = 100;
	let position = 0;
	do{
		position = (position + k) % c.length;
		energy -= 1;
		if (c[position] === 1){
			energy -= 2;
		}
	} while (position !== 0);
	return energy;
}