#### Answer

The point of intersection is $(-8, 180)$.

#### Work Step by Step

We want to find when $f(x) = g(x)$, so we set the two expressions equal to one another and solve:
$3(x^2 - 4) = 3x^2 + 2x + 4$
Use the distributive property:
$3x^2 - 12 = 3x^2 + 2x + 4$
Move all terms to the left side of the equation:
$-2x - 16 = 0$
Factor out common terms:
$-2(x + 8) = 0$
Divide both sides by $-2$:
$x + 8 = 0$
Subtract $8$ from each side of the equation:
$x = -8$
We can now plug this value into either $f(x)$ or $g(x)$ to find the points of intersection of the two graphs. Let's use $f(x)$:
$f(x) = 3[(-8)^2 - 4]$
Evaluate exponents first:
$f(x) = 3(64 - 4)$
Simplify what is in parentheses:
$f(x) = 3(60)$
Multiply to simplify:
$f(x) = 180$
The point of intersection is $(-8, 180)$.