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    print([[i,j,k] for i in range(x+1) for j in range(y+1) for k in range(z+1) if i+j+k != n])

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    if name == 'main': x = int(input()) y = int(input()) z = int(input()) n = int(input())

    perm =[[i,j,k] for i in range(x+1) for j in range(y+1) for k in range(z+1) if i+j+k !=n ]
    
    print(perm)
    
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    I tried this

    list = [[i,j,k] for i in range(0,x+1) for j in range(0,y+1) for k in range(0,z+1)] list2=[] for i in range (0,len(list)): if sum(list[i]) !=n: list2.append(list[i]) print(list2)

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    I was stuck on a coding problem about list comprehensions, but a friend who works in commercial repairing services in London explained it with a real-world analogy now it finally makes sense!

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    comb = [[i,j,k] for i in range(x+1) for j in range(y+1) for k in range(z+1) if (i+j+k) != n]

    print(comb)