gkeswani92 x, y, z, n = int(input()), int(input()), int(input()), int(input()) print ([[a,b,c] for a in range(0,x+1) for b in range(0,y+1) for c in range(0,z+1) if a + b + c != n ])
omalsa04 Looks good, but to avoid those repetitive input calls you could do something like:
x, y, z, n = (int(input()) for _ in range(4))gkeswani92 Thanks for the input. Will use this from now! :D
annnguyen Please explain for me why you use
range(4)
santhoshreddy923 did you got the output for the above one by using list comprehension?
longdangvn88 This expression is used for reducing the repetitive statements in reading the inputs from console.
naseer_shah [deleted]
sohail_shaukat_ range(x,y) will create a range of elements from x to y-1 if only one parameter is passed x is assumed to be 0 so range(y) will create elements in range from 0 till y-1
so here range(4) will create a range which includes 0,1,2,3 hence the loop will iterate 4 times as there are 4 elements
himalayanram_it can you write the complete code snippet using the range(4), I'm getting error. Thanks!
mrrahulgupta0096 it will take 4 inputs i.e from 0 to 3...
gyash919 because we have four variables x,y,z,n
sharmaakhil1998 because there is 4 inputs ! hope you understand
ajaybabuproai3 he want to take input of 4 numbers so in range it counts from 1 then x later until 4 means till n
kaviin27 to get 4 inputs. we are looping the input().
saurabhtumane600 @annguyen bcz its starts from 0 end to 3
paul_schmeida Great tip! BTW is there any reason for using '_' as the dummy variable? What's wrong with using letter, for example 'i'?
gkeswani92 _ is used to signify that even though something is being returned, we don't plan to use that variable any where.
mukeshsinghbhak1 gives the following error in above code in python 2.7.13 : at 0x7f60c947e910>
desmondwongjunl1 You need to put an additional [] in addition to [a,b,c]. Because the output that you want is are lists within a list.
codeharrier It's also an old Perl trick. If you just performed the input command without assigning the data to anything, it was still available in the $_ variable by default.
isaiiswariya [deleted]
vijayvijart284 It just like a while loop (Ex: while(a<5)) . If we need to store in the seperte varible you can use like this x,y,z,a = (int(input()) for n in range(4). It will be stored seperatly
gustavs405 no (lol u w8ted 3yrs 4 answer ;D)
sep2001aryan it depends on programmer what to choose , its your wish
motox2 just a small suggestion ..the 4 in for loop will be n+1
AbhishekVermaIIT N is the number to compare the sum of x, y, z. The loop should actually have 4, as mentioned, for the inputs : x,y,z & n.
newmocart in py2 can be w/o int()
x,y,z,n = [input() for i in range(4)] print [[a,b,c] for a in range(x+1) for b in range(y+1) for c in range(z+1) if a+b+c != n]
bhosalekv Nice solution
deepakumar50136 WHAT IS THE 4 INDICATES HERE
sravan234 range(4) indicates 0,1,2,3 i.e the numbers we have given are allocated to the x,y,z,n respectively
desmondwongjunl1 4 input() s
nick3499 [deleted]karangandhi545 what is the reason for x+1 y+1 and many more
elli0t_4lders0n In simple words it signifies that the range is inclusive of max limit
tpgreene range() is inclusive of the first number (which is 0, by default), but exclusive of the last one. So "for i in range(5): print i" will give you 0,1,2,3,4 (but not five). In this case, we want to also include the number given, hence the +1. The 0 for the first part range(0,5), is optional, since we are starting at the beginning.
shashikantching in python iteration occurs one less than the give variable
alfredocambera Doesn't work on python3.5
akik22 [deleted]
NervousBlakedown I'm using this one line, but my compiler reads "wrong answer". Am I missing something? What else do I need to write?
vammu920 u didnt arrange the list in lexicographic order
NervousBlakedown Disregard, I figured it out.
vammu920 can u send the solution
kumarharsh I am a newbie to python and its not clear to me. WHY 4? And how the variable iterate from 0 to 1.
Code_Lord range(4) means range(0,4) that is 0,1,2,3 which is because we ahve to read 4 inputs Read list comprehensions for more. It is an easy way to build a list.
rahul_rowthi How is this syntax even valid. Just wondering.
codin_kyle I think that _ is used as a dummy variable name. Since it's meaning isn't really significant the name can be something representing that.
Dev_prasad [deleted]
Highlander_Monk Wow nice way to take inputs.
juwelariful [deleted]juwelariful [deleted]sekououattara9 why range (4) ???
hsu_ryan why do i need to add parentheses around
int(input()) for _ in range(4)in order for this code to work?
sep2001aryan coz you have to assign these values to different variables
ayushayush591 in place '_' you should 'n'
sep2001aryan both methods are coprrect :0
mrjomp Makes code less readable, also that doesn't improve time complexity or space complexity so I don't find it that useful other than save some lines of code :S
michaellan202 You can also take in the entire buffer at once with
from sys import stdin x,y,z,n = map(int, stdin.readlines())
benedictwaiharo or you could use functions
WhatsupLucia x, y, z, n = (int(input()) for _ in range(4)) isn't working for me. I'm getting a EOF when reading line error.
Abe10 @vorayash0510, this is great!
aa1992HackerRank Admin nice solution. But instead of range[0,x] you could do
print ([[a,b,c] for a in range(x+1) for b in range(y+1) for c in range(z+1) if a + b + c != n ])
ericali clever!!!
rajasekhariiith [deleted]SuperGogeta Trade three +1's for a +1 and a -1 at the right place :P
x, y, z, n = (int(raw_input())+1 for _ in range(4)) print [[a,b,c] for a in range(x) for b in range(y) for c in range(z) if a+b+c!=n-1]
zhangqunshi although this method is more simple, but it not easy to understand.
yidingyang1027 great!
usaliev I liked this method compared to other's.
james_niroo really like this solution. simple and easy to read
abedsarkil12 [deleted]Dvcks [deleted]
shashiwalker i have done the same thing by its not working ,says invalid syntax
mohana2291 Simple and efficient than mine !! Thanks
rachitajitsaria1 Hey, I have heard that int(raw_input()) is faster.
maximshen raw_input() was renamed to input() in python 3
boler [deleted]rahatchd Can you tell me how python carries out list comprehension internally? How come this generates lists in lexicographic increasing order (i.e z increases first, then y, then x)?
Ryukerg It is in lexographical order due to the nature of the loops. Spaced out it looks somewhat like
for a in range(x+1): for b in range(y+1): for c in range(z+1): if a + b + c != n: print(stuff is here)We start at [0,0,0]. Then c will increment to get to [0,0,1] When c hits [0,0,z], we get [0,1,0] as the next in the loop. This pattern continues and gives us the lexographical ordering required of the output.
BHEEMKUMAR it's very helpfull to understanding that what is actualy asking
masudraj6 Thanks for your solution, now we understand how it's word.
nick3499 [deleted]dangducbac_hust Here is my soltion with your sussgestion:
empty_list = [] for a in range ( x+ 1): for b in range ( y + 1): for c in range ( z + 1): #logic code if (a + b + c != n) : empty_list.append([a,b,c])
print(empty_list)
sheetalparmar899 But my program is not working properly.
krzysztof_jerzy1 Thank you, I really wondered on how it works.
borad_sarita really much helpfull in understanding
nick3499 [deleted]
SanjayDeepu This solution is good! Utilising list comprehension to a good extreme.
trinadhkoya Not reqired to put input() for each variable .just call the input for _ in range(no of variables); see here
a , b = int (input()) for _ in range ( 2 ):
bennetryan Thanks for sharing your elegant code. I'm a newbie to Python, its great to see such beautiful code :)
trinadhkoya to whome you added the comment :)
jonobjornstad great code
andras_lengyel I don't like these "direct print" solutions. In my opinion the problem stated to create a list then print it, not just print something in a list. In other words in your solutions the list itself doesn't exist, can not be used later, it just collected when printed out. What do you think?
andras_lengyel OK, I found the answer! I can put list = instead of printoing out, then print the list. It wasn't clear for me three for loops output is collected in a list, so no need for any append tricks!
ignacio_ch Nice answer. As an alternative, to avoid multiple for loops you can use product:
combinations = list(product(range(x+1), range(y+1), range(z+1))) print([list(a) for a in combinations if sum(a) != n])
davidkobilnyk from itertools import product
18vidhyasagar how is this working?
raspletin it is not solution, as question was to form list comperhention. You just put out data to screen in right format, no list comperhetion created
pH03nYx Could someone explain to me what, exactly, this code does (like, statement-by-statement)(other than the input part I understand that I mostly mean the list comprehension)? I sort of have a basic understanding of how it works, but having some trouble wrapping my head around list comprehensions and how exactly the work. Mostly the "for a in range(0,x+1)" parts. What exactly does that do? Why is it (0,x+1)? Thanks in advance.
madaharishreddy just for curiosity, why you are using range(0,x+1) in the print function?
ldhyim568 why do you need two square brackets? Can someone explain this to me?
janu_s hello.. I tried to do as u said. But it is showing syntax error.
kumar_student101 from itertools import product
print([list(each) for each in product(range(x+1),range(y+1),range(z+1)) if sum(each)!=n])
[deleted] I'm new to python, but how come nobody seems to be using ":" after their for loops. You don't even use one for the if loops at the end.
infnity When you were using for statement inside the print statement you didn't use a colon infront of the for statement???? why was that
chefyunfei exactly what I had, expect I left the 0 implicit. Is it good practice to make the range explicit?
kumar_student101 For this program it is fine. But in real time data range may not be static.
mehdi_jafaree131 no need for 0 in range
Headhunter1 how is list comprehension workin here?
Winkey Good one!!!!
achintya0210 I have no idea what is the syntax error that the compiler is showing repeatedly on (a+b+c)!=n
naveenyadav9515 Thank you very much bro..... i am new to python... initially i din't understand your code but i realized after converting it into normal form. x, y, z, n = int(input()), int(input()), int(input()), int(input()) for i in range(0,x+1): for j in range(0, y + 1): for k in range(0, y + 1): if i + j + k !=n: print([i,j,k])
aliajunisarshaf1 Thanks for your solution!
hakeshkumark why x+1?
mosinpinjar049 wrong answer
yuvi1690 This is not usable with python 3 , shows error..!!
santhoshreddy923 i got it in google chrome but not in edge i dont know the issue
santhoshreddy923 thank you for commenting
nikhilbellad99 this code does print in lexiocgraphy format but not the expected out
thakkarvaibhav7 if possible, can you please explain me how it will how
abhisikta_mishr1 why range x+1
bhupeshjain can be :
print([[a, b, c] for a in range(x + 1) for b in range(y + 1) for c in range( z + 1) if a+b+c != n ])
rnamaye175 print ([[a,b,c] for a in range(0,x+1) for b in range(0,y+1) for c in range(0,z+1) if a + b + c != n ])
sir can you explain this line
sep2001aryan @rnamaye this line print the value of a,b,c from 0 to x+1 , y+1 ,z+1 respectively if the sum (a+b+c) is not equal to the n
rnamaye175 okay sir and one more doubt regarding to that only (a+b+c) !=n
kavithamidde888 Thanks Bro
JaydeepBorkar [deleted]kunal_rana_vps can u explain me the working of this code ??
jkgoyal029 can anyone explain how this code works from print.........
lakshmanpraveen1 Y aare we supposed to run the loop from 0,x+1
yashikesarwani18 why range(0,x+1) ? why x+1 and not x ?
Rahul_7f why range 0 , x+1
Rahulpareek9250 thank you
mogra_nitin14 @gkeswani92 - can you please confirm what will be the order of complexity for this code ? is this still considered a nested loop or is this considered linear ?
tawadeviniket9 x, y, z, n = int(input()), int(input()), int(input()), int(input()) print ([[a,b,c] for a in range(0,x+1) for b in range(0,y+1) for c in range(0,z+1) if x + y+z != n ]) i have written the above code,but it is counting the a+b+c= n entries also..can someone explain why?
sohail_shaukat_ Hi Niket, The problem lies in your if condition, you're running loop with a,b,c but your comparing with it with input limit variables. Try the below snipped of code I'm sharing and this should work :
x, y, z, n = int(input()), int(input()), int(input()), int(input())
print ([[a,b,c] for a in range(0,x+1) for b in range(0,y+1) for c in range(0,z+1) if (a + b + c) != n ])
gabobaby The problem states that it wants the output list printed in 'increasing order'. It should be more clear what this means. I initially interpreted this to mean that [1,1,0] would come before [3,0,0] because 1+1+0=2 is less than 3+0+0=3. But this is not the order that the comprehension list method would generate the list. And would likely involve some method of sorting a 3D array that many new users would not know at this point, so I'm assuming this is not what is meant. This problem is not clarified with the chosen example values of x=1, y=1, z=1, and N=2.
The problem could be addressed by just using larger example values, allowing us to infer from the example output which interpretation of 'increasing order' is intended.
scintilla What does N represent? Why should X+Y+Z not equal N? And what do the subscript i's represent? I don't understand the question.
saikiran9194HackerRank Admin @scintilla read the question properly. 0<=Xi<=X same for Yi and Zi.N is specified in the question.
jhub1 I am sooooooooooooo confused with the question holy cow.
ID10TERROR You can't just say "Read the question properly". He said he doesn't understand the syntax of the question.
This is a type of mathematic short-hand that not all of us understand. I for one don't even know what this short-hand is called or I'd look it up myself.
shashank21jHackerRank Admin Try now, I have updated the statement :)
ID10TERROR Thank you for the follow-up shashank21j, your revision to the statement has been helpful, but I still have some questions about the way the question is worded and why.
1.Why must i+j+k not be equal to N and does this mean it can be greater than N?
2.Please define "lexicographic increasing order"
I for one agree that list comprehension in python is a fairly simple subject, the crux of this problem for me however, is bridging the communication gap/understanding the essance of the problem you're asking.
Many people who use your site are self taught in coding and do not have a formal discrete mathematics background.
shashank21jHackerRank Admin i + j + k != N is just an added condition in this problem so you can use 1 if statement inside your list compehension syntax. It can be greater than N as long as i, j and k are in their respective limits.
- Lexicographic order is sorted order where 1, 1, 1 comes before 1, 1, 2 and 2, 1, 2 comes before 2, 2, 1 etc. etc.
ID10TERROR Thanks again shashank21j! :)
dng304 Shouldn't the statement include that X,Y,Z are integers that are possible maximums? It is a fairly important point no? For example dimensions of 2,2,2 given the statement as it currently is, means there is only 1 possible cube with 8 coordinates.
Where as if we said that 2 is the max integer value for X,Z,Y , we can have more than 1 possible cuboid. For example a 1,1,2 cuboid.
mike_kinny I have also difficulty understanding the question.
cassio_augcs Ok, after hours trying to actually understand the problem, and after trying to solve it in reverse, I hope to bring some clarity for those who are having a hard time trying to solve or to understand what exactly needs to be done and what the codes posted here are actually doing. I did this using Python 3.
Ignoring the mathematical terms, the problem wants you to create a list in a concise way (that's called 'List Comprehension'). Which consists on creating a list using 'for' and, possibly, 'if' (in case you want an extra condition in that list).
In this case, it asks you to create multiple lists using 3 'for' clauses: i, j and k. In each theses clauses you will choose an range to vary from 0, which will be called x (for clause i), y (for clause j) and z (for clause k).
The challenge here is to create every possible list that will show all values from the chosen ranges (x, y and z) in a way that the the predecessor number will change to the next value from the range only AFTER the successor number shows all it's values first.
Before trying an example, first a reminder: As seen in previous challenges, in a 'for' clause, the value of a range will vary (as a standard) from 0 to the predecessor number in that range. I.E.: for A in range(2): will output 0 and 1, but not 2.
Now, let's try to solve it with a simple example: I'll set both, x, y and z to 1, just to make it easier.
This is the formula in a clearer way (not in a single line, but I believe it's best for beginners to understand):
listijk = [] #an empty list to be filled as following for i in range(x + 1): #it will output 0, and will only output 1 after the next conditions ('for j' and 'for k') are met. for j in range (y + 1): #it will output 0, and will only output 1 after the next condition ('for k') is met. for k in range (z + 1): #it will output 0 and then 1. listijk.append([i,j,k]) #it will add i, j and k values to the list print(listijk) #print the list properly filled
(copy and paste the code in an code editor for clearer reading)
In the example above, that's what will happen behind the scenes, in this exact order:
i = 0, j = 0, k = 0
i = 0, j = 0, k = 1
i = 0, j = 1, k = 0
i = 0, j = 1, k = 1
i = 1, j = 0, k = 0
i = 1, j = 0, k = 1
i = 1, j = 1, k = 0
i = 1, j = 1, k = 1
It will print exactly like that:
[0, 0, 0], [0, 0, 1], [0, 1, 0], [0, 1, 1], [1, 0, 0], [1, 0, 1], [1, 1, 0], [1, 1, 1]As you can see, it made 8 different output variations.
Now, to the last part of the problem... It creates one extra condition: it will NOT print the outputs which the sum of the values inherited by i, j and k equals to the integer 'n'.
So, this time, the code will become:
listijk = [] for i in range(x + 1): for j in range (y + 1): for k in range (z + 1): if i + j + k != n: #before printing the result, it will exclude the output which 'i' + 'j' + 'k' is the same as 'n'. listijk.append([i,j,k]) print(listijk)
In this case, let's suppose that 'n' is set to 2:
i = 0, j = 0, k = 0 #will print
i = 0, j = 0, k = 1 #will print
i = 0, j = 1, k = 0 #will print
i = 0, j = 1, k = 1 #will NOT print (1 + 1 = 2)
i = 1, j = 0, k = 0 #will print
i = 1, j = 0, k = 1 #will NOT print (1 + 1 = 2)
i = 1, j = 1, k = 0 #will NOT print (1 + 1 = 2)
i = 1, j = 1, k = 1 #will print
And then, it will print the following 5 outputs:
[0, 0, 0], [0, 0, 1], [0, 1, 0], [1, 0, 0], [1, 1, 1]That's an extense explanation, but I'm just trying to make it as clear as possible for those who, just like me, are having a hard time figuring out what the problem wants and what the codes posted here and in the examples are really doing. Hope it helps someone.
rondina Not wrong, but you have not used list comprehension. Consider a list called 'a' with even and odd numbers. Now suppose you want to create a list 'b' that contains only the even numbers of list 'a'.
One way to do this in the usual way with a loop:
- b = []
- for n in a:
- if n % 2 == 0:
- b.append(n)
Using list comprehension this would look like this single line:
- b = [n for n in a if n % 2 == 0]
The challenge in this problem is creating nested list comprehesions, which can be tricky. See PEP 202.
(Sorry for the broken formatting, but it's not possible to code-format in replies here in HR.)
fisher6 print([[i,j,k] for i in range(x+1) for j in range(y+1) for k in range(z+1) if sum([i,j,k]) != n])
Chemical_a5 This comment taught me list comprehension. Thanks for concise answer.
Tsean Can anybody make me understand this question ? I went through few comments what this question all about but still I'm not clear Please help
eric2013Asked to answer You're given 4 numbers. The first 3 correspond to the maximum dimensions of a cube. y is the maximum height, x is the maximum width, and z is the maximum depth.
You're supposed to calulate every possible set of dimensions [x,y,z], under the condition that none exceed the input values, and that x+y+z does not add up to n.
steeeenos thanks that was very helpful!
shashanksaurav41 Thanks for the explanation eric. I've just one more question that in this lexicographic order the last dimension is [1,1,1], but our N is given to be 2. Thus the sum of x+y+z becomes 3 which is greater than N. How is this condition satisfied?? Pls explain.
eric2013 The only restriction relating to N is that i + j + k != N. i+j+k>N is perfectly valid.
shashanksaurav41 Thanks for your help. Was helpful and appreciate that
sawani_soman92 Helpful explanation! Thank you
dng304 I agree that what you say is the intention of the challenge, But my problem with this challenge is that it never states that X,Y,Z are maximums.
Sample input of 2,2,2 can only be 1 cube with 8 dimensions.
I feel like the statement should be change to express what you are saying, that X,Y,Z correspond to maximum integer dimensions.
jsleirer I feel like I am missing the point of this exercise with my solution. Can someone please comment on how to make my code more pythonesque and utilize list comprehensions better.
X = int(raw_input()) Y = int(raw_input()) Z = int(raw_input()) N = int(raw_input()) Xi = [x for x in range(X+1)] Yi = [y for y in range(Y+1)] Zi = [z for z in range(Z+1)] results = [] for x in Xi: for y in Yi: for z in Zi: if x + y + z != N: results.append([x,y,z]) print resultsshashank21jHackerRank Admin this is fine.
Xi Yi and Zi are not much of use here. You can make your code smaller
stcrestrada cuboid = []
results = [cuboid.append([x, y, z]) for x in range(X+1) for y in range(Y+1) for z in range(Z+1) if x + y + z != N]
print(cuboid)
Less lines, more Pythonic
PRASHANTB1984 That's really great :)
Shriswissfed print ([[a,b,c] for a in range(int(input())+1) for b in range(int(input())+1) for c in range(int(input())+1) if a+b+c!=int(input())])
why does this code not work? can you explain?
vinayshashank The inputs should be captured before the for loop is executed. In this case, a new input is expected for every iteration of the for loop. Try capturing the inputs first inside some variables and use those variables here. That will work.
gkeswani92 You don't even need to have the cuboid list to be honest :)
print ([[a,b,c] for a in range(0,x+1) for b in range(0,y+1) for c in range(0,z+1) if a + b + c != n ])stcrestrada ha!, I realized that a day later. Thanks for clearing it up though gkeswani92
s40_41033 bro can you please explain the code?
Okkie cuboid = [ [i, j, k] for i in range(x + 1) for j in range(y + 1) for k in range(z + 1) if ((i +j + k) != n) ] print(cuboid)
marinskiy Here is Python 3 solution from my HackerrankPractice repository:
x, y, z, n = [int(input()) for _ in range(4)] listOfAnswers = [[i, j, k] for i in range(x + 1) for j in range(y + 1) for k in range(z + 1) if i + j + k != n] print(listOfAnswers)
Feel free to ask if you have any questions :)
jiadaman I'm trying to teach myself Python, and reading this question honestly made me want to give it up. I had no idea what was being asked or how to go about it. If you have the time could you give me an idea of your step by step process for coming to this solution, as far as you can remember? I generally understand what you've done here, but I want to know how to come to a similar conclusion when I encounter a similar problem.
phelipi_mu me too Ç_Ç
danhoffman7 The problem was written very academically. I feel your pain. Weirdly enough they provide an example later on that is actually the answer....
Ive been finding myself working backwards when I 'figure' a hard problem. I usually don't know why the solution works, so I try to reverse engineer all the elements that work it.
[[l,j,k] for l in range(x+1) for j in range(y+1) for k in range(z+1) if ((j+l+k) != n)]
we create a placeholder list [l,j,k] that iterates over a range from zero to the provided integers. since range is not inclusive, we can find this range by saying range(x+1) since it will provide a list of 0...1...2. we then define how each placeholder int iterates by each subsequent range declaration. After we provide the context of the iteration, we provide an if statement that the sum of all three iterables can't equal n. How the heck the computer does that magic...I don't know.
Someone correct me but this is the best I understand the solution. Even if I'm very wrong, just explaining it helps me understand it.
Codetuer MeToo
s40_41033 bro can you please explain the code?
richakulshresta I m not able to understand the problem here, can somebody help me
JayMiro I think they want us to get four inputs e.g.
1 # X
2 # Y
3 # Z
4 # N
This means we have a 3D cuboid with 0 and 1 on the X direction, 0, 1, 2 on the Y direction and 0, 1, 2, 3 on the Z direction. These are a total of 2 x 3 x 4 nodes. At each of theese nodes we have to check if the sum of the node indices is equal to N. If it is not equal to N we will add this list to the list of nodes. E.g. if we look at the note (0, 0, 0) the sum of all the indices is equal to 0 which is clearly not equal to N = 4. Hence we append this node to our list and get [[0, 0, 0]]. Then we procede until we have checked every possible combination.
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