• + 4 comments

    People are using many techniques but i consider the easiest to be XOR gate.This question is meant to be solved using Xor gate. Here is my Code-

    #include <iostream>
    using namespace std;
    int main()
    {
    	int n;
    	cin>>n;
    	int ans=0;
    	for(int i=0;i<n;i++)
    	{
    		int x;
    		cin>>x;
    		ans^=x;
    	}
    	cout<<ans<<endl;
    }