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Nice idea of modReverse! With that a linear (not quadratic) recurrent approach is possible.
Can any one explain how to get 14 from n=3? 3*1 + 3*2 + 1*6 = 15.
@sentinel45: Please explain generation of catalan number in editorial solution in depth.
Hi you can refer http://en.wikipedia.org/wiki/Catalan_number
The formula in the link that used is Cn+1 = (2*(2n+1)*Cn)/(n+2)
and n can be stored in 32 bit integer. Then, why is it necessary to calculate modInverse or generateInverse while we can directly use (n+2) ?????
Please explain me...
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