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For C:
int magic_mat[8][3][3] = { {{8, 1, 6}, {3, 5, 7}, {4, 9, 2}}, {{6, 1, 8}, {7, 5, 3}, {2, 9, 4}}, {{4, 9, 2}, {3, 5, 7}, {8, 1, 6}}, {{2, 9, 4}, {7, 5, 3}, {6, 1, 8}}, {{8, 3, 4}, {1, 5, 9}, {6, 7, 2}}, {{4, 3, 8}, {9, 5, 1}, {2, 7, 6}}, {{6, 7, 2}, {1, 5, 9}, {8, 3, 4}}, {{2, 7, 6}, {9, 5, 1}, {4, 3, 8}}, }; int A[3][3]; for (int i = 0; i < 3; i++) { for (int j = 0; j < 3; j++) scanf("%d", &A[i][j]); } int min_cost = 81; for (int k = 0; k < 8; k++) { int crt_cost = 0; for (int i = 0; i < 3; i++) { for (int j = 0; j < 3; j++) crt_cost += abs( A[i][j] - magic_mat[k][i][j] ); } if (crt_cost < min_cost) min_cost = crt_cost; } printf("%d", min_cost);
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Forming a Magic Square
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For C: