• + 5 comments

    A little bit simpler:

    Python 3

    s = [[int(i) for i in input().split(' ')] for j in range(3)]
    n = [s[i][j] for i in range(3) for j in range(3)]    
    all_n = [[8,1,6,3,5,7,4,9,2],[6,1,8,7,5,3,2,9,4],[4,9,2,3,5,7,8,1,6],[2,9,4,7,5,3,6,1,8],[8,3,4,1,5,9,6,7,2],[4,3,8,9,5,1,2,7,6],[6,7,2,1,5,9,8,3,4],[2,7,6,9,5,1,4,3,8]]
    
    allsum = []
    for l in all_n:
        allsum.append(sum([abs(n[i]-l[i]) for i in range(9)]))
    print(min(allsum))