Making Anagrams

  • + 5 comments

    passed all test cases in 0s

    string in1,in2;
    cin>>in1>>in2;
    int array[26] = {0};
    for(int i=0;i<in1.length();i++)
        array[in1[i]-'a']++;
    for(int i=0;i<in2.length();i++)
        array[in2[i]-'a']--;
    int sum = 0;
    for(int i=0;i<26;i++)
        sum+=abs(array[i]);
    cout<<sum;
    return 0;