njonjiop The regex should imho start with ^ and end with a $, however this is not accepted. This seems contradictory in comparison with the previous question where it was required.
tonghe I used ^ and $ just as last question required. And it was wrong. The test cases are not consistent. Really confusing.
menafgul testcase#4 for javascript is this "10a10.2015452254" and expects "true". this should be fixed.
k_pawlowski I had the same problem. Solution was not to use ^$ as it was needed in the previous one example...
dicky_dicky yes, test case 4 is broken :(
pratik9044536615 Yup for the last part check for atleast 4 digits i.e. minimum 4 and max can be any
191997mahesh if use ^ and $ then it will restrict to 4 digits, so the case goes wrong, without them the case will pass
quixrick Yeah, I used the ^, but could not use the $ as it would fail. If it said that it could be an arbitrary number of digits, instead of xxXxxXxxxx, then it would have made more sense.
ganjash ya, this should be fixed. It should false.
minatocool20119 (\d{2}\D){2}\d{4} because "a" and "." are character xxXxxXxxxx
vishal_chitnis It's easier to group digits like \d{2} rather than \d\d
britojr This is annoying: I got WA on previous challenge because I didn't use ^ and $ for begin and end of the expression.
But in this one I got WA because I used those.
So, it's never clear if the expression should or shouldn't accept strings that have something exra after the match
zhanyu_wang It's confusing when in the problem "Matching Anything But a Newline" we have to use "^" and "$" but now we should not.
mkhanw01 (\d{2}\D){2}\d{4}
sguti As everyone is saying test case 4 is broken. Will it ever be fixed?
osho_agyeya Why use
"\\d"
instead of "\d" in Java 8?
gowriaddepalli ^\d\d\D\d\d\D(\d\d)+$ worked for me in java 7
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