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  1. Prepare
  2. Regex
  3. Introduction
  4. Matching Specific String
  5. Discussions

Matching Specific String

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68 Discussions

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  • arohi_agrawal111
     + 0 comments

    Python3

    Regex_Pattern = r'hackerrank'

import re

Test_String = input()

match = re.findall(Regex_Pattern, Test_String)

print("Number of matches :", len(match))

  • jhong78625
     + 0 comments

    \w{3}\W\w{10}\W\w{3}

  • preethiannjacob
     + 0 comments

    Java 15:

    import java.io.*;
import java.util.*;
import java.util.regex.Pattern;
import java.util.regex.Matcher;

public class Solution {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        Pattern pattern = Pattern.compile("hackerrank");
        int count = 0;
        while(sc.hasNext())
        {   Matcher matcher = pattern.matcher(sc.next());
            if (matcher.find()) count++;
        }
        System.out.println("Number of matches : "+count);
    }
}

  • estevaopbsantos
     + 0 comments

    java solution

    import java.io.*;
import java.util.*;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Solution {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        Pattern pattern = Pattern.compile("hackerrank");
        int count = 0;
        while (scanner.hasNext()) {
            Matcher matcher = pattern.matcher(scanner.next());
            if (matcher.find()) count++;
        }
        System.out.println("Number of matches : " + count);
    }
}

  • tonton0880
     + 0 comments

    This got me confused, I thought what the task wants is to search characters between the "." in example URL. so I used this regex "(?<=.).(?=.)" however it seems it only requires to search for "hackerrank" string only. My reading comprehension is too rusty.