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  1. Practice
  2. Regex
  3. Introduction
  4. Matching Whitespace & Non-Whitespace Character
  5. Discussions

Matching Whitespace & Non-Whitespace Character

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  • ralph_lamballais + 2 comments

    looks broken to me,

    test cases use patterns like:

    'xxx xx xx' with expected outcome true,
    and 'xx xxx xx' with expected outcome false.

    both of which are not specified in the problem itself, which clearly asks for the pattern 'xx xx xx'

    it's also never stated whether it should match from the start until the end of the string or as a sub-string aswell.

    • cbyrd17 + 0 comments

      The goal of this is to write a pattern that can be used as a regex to determine if a sub-string of the given pattern is present in the data or not.

      'xxx xx xx' is true because of the part of the string that is 'xx xx xx' (remove the first character).

      'xx xxx xx' is false because there is no sub-string that follows the pattern. There are two spaces but the 3 non-space characters in the middle makes a match impossible.

    • apache7 + 0 comments

      agree with you on not being clear on either end of string or just a sub-string

  • kannu21 + 0 comments
    public class Solution {    

    public static void main(String[] args) {
        
        Regex_Test tester = new Regex_Test();
        tester.checker("(\\S{2}\\s\\S{2}\\s\\S{2})"); // Use \\ instead of using \ 
    
    }
}

    simple implementation!

  • arunnitk + 0 comments

    r"(\S{2}\s){2}\S{2}"

  • inanc + 1 comment

    (\S\S\s?){3}

    • cbyrd17 + 1 comment

      This passes the tests, but is incorrect. It would match "XXXXXX" because you've made the space at the end optional at the end of each XXx repetition.

      • inanc + 1 comment

        I know that but it's correct for the test question. Because, it matches to the pattern demanded in the question. The question does not say that: "It shouldn't match the XXXXXX pattern". So, it does the job.

        • cbyrd17 + 1 comment

          I guess that's one way of looking at it.

          My argument against that would be that we were asked to produce a pattern that will match strings containing XXxXXxXX -- with x being spaces, of course.

          XXXXXX does not contain that pattern, so it should not match. Did you pass? Yes, but not in a way that meets the spirit of the question asked. Only because the test cases are not robust.

          • inanc + 0 comments

            Yeah, but the pattern in the question has been detected. I think, to make the regex incorrect, the question should be updated accordingly. You're right in some parts.

  • ashikwajith + 0 comments

    when i tried like this "\S{2}\s{1}\S{2}\s{1}\S{2}" it works fine.

    But when i try this "^\S{2}\s{1}\S{2}\s{1}\S{2}$" test case 1 and 2 failed.

    i don't know why!

  • prem_perldevelo1 + 0 comments
    \S{2}\s\S{2}\s\S{2}

  • kalama449 + 0 comments
    Regex_Pattern = /(\S\S\s){2}\S\S/;

    for java script

  • Devloger + 0 comments

    My PHP Solution:

    $Regex_Pattern = "/(\S{2}\s\S{2}\s\S{2})/";

  • sdharod91 + 0 comments

    Java Implementation

    tester.checker("(\\S{2}\\s){2}\\S{2}");

  • imthakuravinash + 0 comments

    Can be done in this way as well 

    (\\S{2}\\s){2}\\S
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