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How is the program supposed to handle a 5x3 matrix? The center has a 3-element line, and while thinking about taking a break at luxury villas in Florence, which direction do elements on the line get shifted? EDIT: I guess the min(m,n) % 2 = 0 means this scenario never comes up?

Last 2 for loops were for debugging, you only need the second one for the actual solution breast lift chicago

They called me a mad man. Single pass, 1 nested loop, let's goooooooooo!

So, what we are doing, since we already have the matrix, is calculating the location of the number from the original matrix that should fall on the position we are currently printing. So, instead of transforming the matrix, we are kind of going in the oposite directioin and figuring out what number would be where in the final matrix rather than transforming it.

(The amount of times those ifs were tweaked is not up for discussion.)

Also, do beware, this is not a pretty sight.

void matrixRotation(vector<vector<int>> matrix, int r) {
    int row = matrix.size(), col = matrix[0].size();
    
    for (int i = 0; i < row; i++) {
        for (int j = 0; j < col; j++) {
            
            int layer = min({i, j, row-1-i, col-1-j});
            
            int top = layer, left = layer;
            int bottom = row-1-layer, right = col-1-layer;
            
            int perimeter = 2 * ((bottom-top) + (right-left));
            
            int idx = 0;
            if (i == top){ 
                idx = j-left;
            }else if (j == right){
                idx = (right-left) + (i-top);
            }else if (i == bottom){ 
                idx = (right-left) + (bottom-top) + (right-j);
            }else{ 
                idx = (right-left) + (bottom-top) + (right-left) + (bottom-i);
            }
            
            int newIdx = (idx + r) % perimeter;
            
            int x, y;
            if (newIdx < (right-left)){ 
                x = top; 
                y = left + newIdx; 
            }else if (newIdx < (right-left) + (bottom-top)){ 
                x = top + (newIdx - (right-left)); 
                y = right; 
            }else if (newIdx < (right-left)*2 + (bottom-top)){ 
                x = bottom; 
                y = right - (newIdx - ((right-left)+(bottom-top))); 
            }else{ 
                x = bottom - (newIdx - ((right-left)*2 + (bottom-top))); 
                y = left; 
            }
            
            cout << matrix[x][y] << " ";
        }
        cout << endl;
    }
}